Answer:
The values for expression is h = - 2 and k = 5
Step-by-step explanation:
Given algebraic expression can be written as :
2 x³ - 10 x² + 11 x - 7 = ( x - 4 ) × ( 2 x² + h x + 3 ) + k
Now opening the bracket
Or, 2 x³ - 10 x² + 11 x - 7 = x × ( 2 x² + h x + 3 ) - 4 × ( 2 x² + h x + 3 ) + k
Or, 2 x³ - 10 x² + 11 x - 7 = 2 x³ + h x² + 3 x - 2 x² - 4 h x - 12 +k
Or , 2 x³ - 10 x² + 11 x - 7 = 2 x³ + ( h - 2 ) x² + ( 3 - 4 h ) x - 12 + k
Now, equating the equation both sides
I.e - 10 = ( h - 2 )
Or , h - 2 = - 10
I.e , h = - 10 + 2
∴ h = - 2
Again , 11 = ( 3 - 4 h )
or, 11 = 3 - 4 h
or, 11 - 3 = - 4 h
or, 8 = - 4 h
∴ h = 
I.e h = - 2
Again
- 7 = - 12 + k
Or, k = - 7 + 12
∴ k = 5
Hence The values for expression is h = - 2 and k = 5 . Answer
The answer to the question is: Yes.
Explanation: It can be solved by following exactly the same procedures
that solved the other two questions that you posted within the past 15 minutes.
Since I'm here already, here is the solution to this one:
6x² + 18x = 0
Divide each side of the equation by 6 :
x² + 3x = 0
Factor the left side:
x(x+ 3) = 0
This statement is true if x=0 or if x=3.
The solution to this one is even the same as the solution to the last one you posted.
You really ought to take a break, go back, review the solutions you've been given,
and try to solve a few on your own.
Answer:
f(5)=-1
Step-by-step explanation:
Answer:
¼
Step-by-step explanation:
The probability of having a boy is ½ and that of a girl is ½.
Probability of boy, boy is (pb*pb) and given pb to be ½ then we can prove the point as follows
For these two children
The options are as follows
1 boy(first) and 1 girl
2 boys
2 girls
1 girl( first) and 1 boy
These are four possible options and the option for two boys is 1 out of the four.
The probability of 2 boys is ½*½=¼
Answer:
0
Step-by-step explanation:
subtract 20 from 40 it's Zero
