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2 years ago

18)

Mathematics

1 answer:

kondor19780726 [428]2 years ago

7 0

If the circumference of a circle is changed from 9 cm to 3 cm, then the diameter decreases by a factor of 3.

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Mishka is on a long road trip, and she averages 75 mph for 2 hours while she's driving on the highway. While she's driving on si

slega [8]

If she goes 75 mph for 2 hours, that's 150 miles altogether. 45 mph for 1 hour is 45 miles, so 150 + 45 is 195 miles.

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3 years ago

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A line passes throught the origin (-1, 1) and (4, n). Find the value of n. enter the correct answer in the box. I'd say (4, -2)

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3 years ago

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3 years ago

Below the function h (x) ang g (x) are graphes. At which values of x is true that h (x) > g (x)? Select all that apply.

rodikova [14]

Answer:

Step-by-step explanation:

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3 years ago

Select the two values of x that are roots of this equation.<br> 2x^2+ 1 = 5x

iren [92.7K]

Answer:

$\frac{5+\sqrt{17}}{4}$ , $\frac{5-\sqrt{17}}{4}$

Step-by-step explanation:

One is asked to find the root of the following equation:

$2x^2+1=5x$

Manipulate the equation such that it conforms to the standard form of a quadratic equation. The standard quadratic equation in the general format is as follows:

$ax^2+bx+c=0$

Change the given equation using inverse operations,

$2x^2+1=5x$

$2x^2-5x+1=0$

The quadratic formula is a method that can be used to find the roots of a quadratic equation. Graphically speaking, the roots of a quadratic equation are where the graph of the quadratic equation intersects the x-axis. The quadratic formula uses the coefficients of the terms in the quadratic equation to find the values at which the graph of the equation intersects the x-axis. The quadratic formula, in the general format, is as follows:

$\frac{-b(+-)\sqrt{b^2-4ac}}{2a}$

Please note that the terms used in the general equation of the quadratic formula correspond to the coefficients of the terms in the general format of the quadratic equation. Substitute the coefficients of the terms in the given problem into the quadratic formula,

$\frac{-b(+-)\sqrt{b^2-4ac}}{2a}$

$\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}$

Simplify,

$\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}$

$\frac{5(+-)\sqrt{25-8}}{4}$

$\frac{5(+-)\sqrt{17}}{4}$

Rewrite,

$\frac{5(+-)\sqrt{17}}{4}$

$\frac{5+\sqrt{17}}{4}$ , $\frac{5-\sqrt{17}}{4}$

8 0

3 years ago