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finlep [7]
3 years ago
12

How do you solve the equation (X+3)^3=81

Mathematics
1 answer:
solmaris [256]3 years ago
4 0
(x+3)^3=81\\
x+3=\sqrt[3]{81}\\
x+3=3\sqrt[3]3\\
x=3\sqrt[3]3-3\\

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Answer:

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Step-by-step explanation:

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So, we have:

x_1 = \frac{56 + 64}{2} = 60

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And so on

So, the table becomes:

\begin{array}{cc}{x} & {f} & {60} & {11} & {69} & {15} & {78} & {14} & {87} & {4} & {96} & 11 \ \end{array}

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The variance is:

\sigma^2 = \frac{\sum f(x - \bar x)^2}{\sum f - 1}

So, we have:

\sigma^2 = \frac{(60 - 76.2)^2*11+(69 - 76.2)^2*15+(78 - 76.2)^2 *14+(87 - 76.2)^2*4+(96 - 76.2)^2*11}{11+15+14+4+11-1}

\sigma^2 = \frac{8488.8}{54}

\sigma^2 = 157.2

The sample standard deviation is:

\sigma = \sqrt{\sigma^2

\sigma = \sqrt{157.2

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Solving (b): The sample variance

In (a), we calculate the sample variance to be:

\sigma^2 = 157.2

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Step-by-step explanation:

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