Answer:
2.50
Step-by-step explanation:
The average rate of change over the interval −2≤x≤2 is:
(f(2) − f(-2)) / (2 − -2)
From the table, we see that f(2) = 14 and f(-2) = 4.
(14 − 4) / (2 − -2)
10 / 4
2.50
It would then be 500m+1000 and the total paid aka the T would change
Let x be the measure of leslie wing
insect wing=1m=100cm
insect wing= 1/10 of leslie wing
100cm=1/10 *x
1000cm=x
x=1000cm
x=10m
therefore the leslie wing = 10m
Answer:
9.01
Step-by-step explanation:
10.00-15%+6%=9.01
Answer:
(a) x² − 13x + 4
(b) x² − 26x + 153
Step-by-step explanation:
f(x) = x² + 3x − 2
a + ß = -3
aß = -2
(a) (x − a²) (x − ß²)
x² − (a² + ß²) x + a²ß²
x² − ((a + ß)² − 2aß) x + a²ß²
x² − ((-3)² − 2(-2)) x + (-2)²
x² − (9 + 4) x + 4
x² − 13x + 4
(b) (x − (a − ß)²) (x − (a + ß)²)
x² − ((a − ß)² + (a + ß)²) x + (a − ß)²(a + ß)²
x² − (a² − 2aß + ß² + a² + 2aß + ß²) x + (a² − 2aß + ß²)(a + ß)²
x² − (2a² + 2ß²) x + (a² − 2aß + ß²)(a + ß)²
x² − 2(a² + ß²) x + (a² − 2aß + ß²)(a + ß)²
x² − 2((a + ß)² − 2aß) x + ((a + ß)² − 4aß)(a + ß)²
x² − 2((-3)² − 2(-2)) x + ((-3)² − 4(-2))(-3)²
x² − 2(9 + 4) x + (9 + 8)(9)
x² − 26x + 153
