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umka2103 [35]
3 years ago
11

A particle moves along line segments from the origin to the points (3, 0, 0), (3, 4, 1), (0, 4, 1), and back to the origin under

the influence of the force field F(x, y, z) = z^2i + 4xyj + 5y^2k. Use Stokes' Theorem to find the work done.
Mathematics
1 answer:
LiRa [457]3 years ago
8 0

Answer:

the first option because I took the test

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Triangle abc has the angle mesausres shown. Which statement is true about the angles?
Umnica [9.8K]

Answer:

m∠A = 20°

Step-by-step explanation:

Given that the sum of the angles of any triangle is 180°, adding the expressions of each angle and setting them equal to 180° will give the value of 'x' and allow you to evaluate the angles.  

2x + 5x + 11x = 180

18x = 180

18x/18 = 180/18 or x = 10

m∠A = 2x or 2(10) = 20°

m∠B = 5x or 5(10) = 50°

m∠C = 11x or 11(10) = 110°

Out of the choices given, the only one that is true is that m∠A = 20°.

8 0
3 years ago
PLEASE HELP ME I HAVE NO CLUE WHAT THE ANSWER IS PLEASE HELPPP!!!!!!!!
shusha [124]

Answer:

I think C

Step-by-step explanation:

oh god sorry if you get this wrong im so sorry.

7 0
3 years ago
-x+4=2x-8<br><br> We think it’s x=11.5
kvv77 [185]

Answer:

x=4

Step-by-step explanation:

-x+4=2x-8

4=2x-(-x)-8

4=2x+x-8

4=3x-8

3x=4+8

3x=12

x=12/3

x=4

6 0
4 years ago
Solve the proportion75.5x=2451 , rounding your answer to the nearest tenth.
guapka [62]
The slope is 32.5 rounded to the nearest tenth
3 0
3 years ago
Write a quadratic function in standard form with zeros 1 and -10
Licemer1 [7]

Answer:

f(x)=x^2+9x-10

Step-by-step explanation:

<u>Standard Form of Quadratic Function</u>

The standard form of a quadratic function is:

f(x)=ax^2+bx+c

where a,b, and c are constants.

The factored form of a quadratic equation is:

f(x)=a(x-\alpha)(x-\beta)

Where \alpha and \beta are the roots or zeros of f, and a is constant.

We know the zeros of the function are 1 and -10. The function is:

f(x)=a(x-1)(x-(-10))

f(x)=a(x-1)(x+10)

Operating:

f(x)=a(x^2+10x-x-10)

Joining like terms:

f(x)=a(x^2+9x-10)

Since we are not given any more restrictions, we can choose the value of a=1, thus. the required function is:

\boxed{f(x)=x^2+9x-10}

6 0
3 years ago
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