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ICE Princess25 [194]
3 years ago
6

A car purchased in 2014 was worth $21,000. It has depreciated at an annual rate of 8.5%. what will its value be in 2021?

Mathematics
1 answer:
liraira [26]3 years ago
6 0

Answer: The value of the car in 2021 will be $11,276.31.

Step-by-step explanation:

If r is the depreciation rate and P is the initiial amount , then the amount after t years is given by:-

A=P(1-\dfrac{r}{100})^t

Given: P=21000, r=8.5%  , t= 2021-2014= 7

Plug all the values in the formula, we get

A= 21000(1-\dfrac{8.5}{100})^7\\\\\Rightarrow\ A=21000(1-0.085)^7\\\\\Rightarrow\ A= 21000(0.915)^7\\\\\Rightarrow\ A= 21000(0.5369670)\approx11276.31

The value of the car in 2021 will be $11,276.31.

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Answer:

* The monthly mortgage payment is $629.53 ⇒ answer C

Step-by-step explanation:

* Lets explain how to solve the problem

- Leila is considering buying her first home

- The house she is interested in buying is priced at $125,000

∴ She can put $20000 down  payment

* Lets find the balance to be paid off on mortgage

∴ The balance = 125000 - 20000 = 105000

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* Lets find the rule of the monthly payment

∵ pmt=\frac{\frac{r}{n}[P(1+\frac{r}{n})^{tn}]}{(1+\frac{r}{n})^{tn}-1} , where  

- pmt is the monthly mortgage payment

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∵ r = 6/100 = 0.06

∵ n = 12

∵ t = 30

∴ pmt=\frac{\frac{0.06}{12}[105000(1+\frac{0.06}{12})^{30(12)}}{(1+\frac{0.06}{12})^{30(12)}-1}

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