1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jasenka [17]
3 years ago
9

Oxidation can be defined as_______ question 4 options: increase in oxidation number decrease in oxidation number gain of electro

n non of the above
Chemistry
1 answer:
KiRa [710]3 years ago
8 0
If you combine zinc with apple juice it is toxic.

You might be interested in
Pesticide concentrations in the Rhine River between Germany and France between 1969 and 1975 averaged 0.55 mg/L of hexachloroben
sertanlavr [38]

Answer:

1.93×10⁻³ mmoles/L of C₆Cl₆; 1.58×10⁻⁴ mmoles/L of C₁₂H₈Cl₆O; 3.51×10⁻³ mmoles/L of C₆H₆Cl₆

Explanation:

We have to find out the molar mass of each pesticide to calculate the moles, and then the milimoles

C₆Cl₆ → 12. 6 + 35.45 .6 = 284.7 g/m

C₁₂H₈Cl₆O →  12 . 12 + 8.1 + 35.45 .6 + 16 = 380.7 g/m

C₆H₆Cl₆ → 12.6 + 6.1 + 35.45 .6 = 290,7 g/m

Let's convert mg to g (/1000)

0.55 mg / 1000 = 5.5×10⁻⁴ g

0.060 mg / 1000 = 6×10⁻⁵ g

1.02 mg / 1000 = 1.02×10⁻³ g

Now we can know the moles (mass / molar mass)

5.5×10⁻⁴ g / 284.7 g/m = 1.93×10⁻⁶ moles of C₆Cl₆

6×10⁻⁵ g / 380.7 g/m = 1.58×10⁻⁷ moles of C₁₂H₈Cl₆O

1.02×10⁻³ g / 290,7 g/m = 3.51×10⁻⁶ moles of C₆H₆Cl₆

Milimoles = Mol . 1000

1.93×10⁻⁶ . 1000 = 1.93×10⁻³ mmoles of C₆Cl₆

1.58×10⁻⁷ . 1000 = 1.58×10⁻⁴ mmoles of C₁₂H₈Cl₆O

3.51×10⁻⁶ . 1000 = 3.51×10⁻³ mmoles of C₆H₆Cl₆

6 0
3 years ago
Why do most leaves appear green​
expeople1 [14]
The chlorophyll inside the leaves
3 0
2 years ago
Read 2 more answers
A six row combin harvests 266 pounds of corn per min. How many bushels of corn does it harvest per hour? (Note: 1 Bu = 56 Lbs) R
kiruha [24]

Answer:

The six-row combin harvests 285 bushels of corn per hour.

Explanation:

The rule of three or is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them. That is, what is intended with it is to find the fourth term of a proportion knowing the other three.

If the relationship between the magnitudes is direct, you can apply the following formula:

a ⇒ b

c ⇒ x

So: x=\frac{a*b}{c}

In this case you can apply it in the following way: if 56 pounds is equal to 1 bushel, 266 pounds to how many bushels is it?

x=\frac{266 pounds*1 bushel}{56 pounds}

x=4.75

This is, a six row combin harvests 4.75 bushels of corn per min.

So, being 1 hour equal to 60 minutes, you can apply the following rule of three: if in 1 minute a six-row harvester harvests , in 60 minutes how many bushels of corn it harvests?

bushels of corn=\frac{60 minutes*4.75 bushels of corn}{1minute}

bushels of corn=  285

<u><em> The six-row combin harvests 285 bushels of corn per hour.</em></u>

5 0
3 years ago
The factor that has the biggest effect on the climate of a region is generally _____.
NemiM [27]

Answer:

C

Explanation:

Closer to equator means temp high more humidity and more hot

Further form equator cold temp less sun more cold

3 0
3 years ago
A chemist designs a galvanic cell that uses these two half-reactions: half-reaction standard reduction potential (s)(aq)(aq)(l)
miv72 [106K]

Answer:

Reduction (cathode): Cu²⁺(⁺aq) + 2 e⁻ → Cu(s)  

Oxidation (anode): Zn(s) → Zn²⁺(⁺aq) + 2 e⁻        

Cu²⁺(⁺aq) + Zn(s) → Cu(s) + Zn²⁺(⁺aq)

E°cell = 1.10 V

Explanation:

<em>The half-reactions are missing, but I will propose some to show you the general procedure and then you can apply it to your equations.</em>

<em>Suppose we have the following half-reactions.</em>

<em>Cu²⁺(⁺aq) + 2 e⁻ → Cu(s)   E°red = 0.34 V</em>

<em>Zn²⁺(⁺aq) + 2 e⁻ → Zn(s)    E°red = -0.76 V</em>

<em />

To identify how to make a spontaneous cell, we need to consider the standard reduction potentials (E°red). The half-reaction with the higher E°red will occur as a reduction (in the cathode), whereas the one with the lower E°red will occur as an oxidation (in the anode).

Reduction (cathode): Cu²⁺(⁺aq) + 2 e⁻ → Cu(s)   E°red = 0.34 V

Oxidation (anode): Zn(s) → Zn²⁺(⁺aq) + 2 e⁻        E°red = -0.76 V

To get the overall equation we add both half-reactions.

Cu²⁺(⁺aq) + Zn(s) → Cu(s) + Zn²⁺(⁺aq)

The standard cell potential (E°cell) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E°cell = E°red, cat - E°red, an

E°cell = 0.34 V - (-0.76 V) = 1.10 V

Since E°cell > 0, the reaction is spontaneous.

5 0
3 years ago
Other questions:
  • I NEED HELPP<br> Describe how carbon and oxygen form carbon dioxide.
    12·2 answers
  • An object is uniformly accelerated from rest to a speed of 35 meters per second in 7 seconds. The acceleration of the object is
    8·2 answers
  • A sample of ammonia gas at 298 K has a volume of 3.5 L at a pressure of 170.2 kPa, what is the new pressure if the gas is compre
    11·2 answers
  • In the Sandwiches mode, select the "Cheese" option and observe the equation given for the preparation of a cheese sandwich. When
    12·1 answer
  • If kb for nx3 is 4.0×10−6, what is the poh of a 0.175 m aqueous solution of nx3?
    12·1 answer
  • 26. Which type of element has properties that are intermediate between metals and nonmetals?
    12·1 answer
  • Math is hard don’t report me I have a question
    7·1 answer
  • Which formula is comparing a sample of a gas under two different conditions of volume and temperature, if the pressure is consta
    8·1 answer
  • 7. What do all elements in the same period on the periodic table have in common?
    6·1 answer
  • The solubility of lead(II) chloride is 0.45 g/100 mL of solution. What is the Ksp of PbCl2?a. 8.5 ? 10^-6b. 4.2 ? 10^-6c. 1.7 ?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!