The chemical formula for ammonium oxalate is C2H8N2O4
We can rephrase the statement with a little more specificity in order to understand the answer here.
The mass of the products can never be more than the The mass that is expected.
Equation of decomposition of ammonia:
N2+3H2->2NH3
Euilibrium constant:
Kc=(NH3)^2/((N2)((H2)^3))
As concentration of N2=0.000105, H2=0.0000542
so equation will become:
3.7=(NH3)^2/(0.000105)*(0.0000542)^3
NH3=√(3.7*0.000105*(0.0000542)^3)
NH3=7.8×10⁻⁹
So concentration of ammonia will be 7.8×10⁻⁹.
Answer:
1.35 m
Explanation:
We can solve this problem by using the <em>freezing point depression formula</em>:
Where:
- ΔT is the temperature difference between the freezing point of the pure solvent (water) and the solution. In this case it is (<em>0 °C - -2.5 °C = 2.5 °C</em>).
- Kf is the cryoscopic constant, <em>for water it is 1.853 °C*kg/mol.</em>
- i is the van't Hoff factor, <em>as sugar does not dissociate in water, it has a value of 1</em>.
We <u>input the data</u>:
- 2.5 °C = 1.853 °C*kg/mol * m * 1
And <u>solve for m</u>:
