PLEASE HELP<br><br> An example problem for multiplying or dividing integers with a different sign.

John has a job selling souvenirs on a football stadium. He earns $10 per game plus $0.25 dollars for each souvenir he sells. How

Ahat [919]

Answer:

He needs to sell 100 souvenirs

Step-by-step explanation:

We want to know the number of souveniers John has to sell

Let the number of souveniers he sold at the game be s

At a rate of $0.25 per souvenier, the amount earned on souveniers for s souveniers will be:

$0.25 \times s =0.25s$

Now, if we added this to the amount he earns per game, we will have the total $35 earned for working at one game.

Thus, mathematically:

$0.25s + 10 = 35 \\ 0.25s = 35 - 10 \\ 0.25s = 25 \\ s = \frac{25}{0.25} \\ s = 100$

7 0

2 years ago

help please !!!Kevin wants to make a mixture that is 50% lemon juice and 50% lime juice. How much 100% lemon juice should he add

Liula [17]

So basically, he wants to make mixture where lemon=lime

it is 6 gallons so
40% of 6=0.4 times 60=2.4=lemon
60% of 6=0.6 times 60=3.6=lime
so to make them equal
3.6-2.4=1.2
he must add 1.2 gallons of 100% lemon juice to make a mixture of 50% lemon and 50% lime

1.2 gallons is the answer

8 0

3 years ago

You have decided to purchase a car for $25,625. The credit union requires a 10% down payment and will finance the balance

swat32

Answer:

Total purchase = $28498.685

In cent = 2849868.5 cent.

Step-by-step explanation:

Given : You have decided to purchase a car for 175.13.

To find : What is the total purchase price of the car including tax, license, and title?

Solution :

Price of car = $25,625

Sales tax = 7.5% = 0.075

The total purchase price of the car including tax is

T=25625\times 0.075=\$1921.875T=25625×0.075=$1921.875

Title charges are $175.13.

The credit union requires a 10% down payment and will finance the balance with a 9% annual interest loan for 36 months.

10% down payment on price of car

25625\times 0.10=2562.525625×0.10=2562.5

25625-2562.5=23062.525625−2562.5=23062.5

The amount will be $23062.5

Now, we find the monthly payment,

Monthly payment, M=\frac{\text{Amount}}{\text{Discount factor}}M=

Discount factor

Amount

Discount factor D=\frac{1-(1+i)^{-n}}{i}D=

i

1−(1+i)

−n

Rate = 9%=0.09

i=\frac{0.09}{12}=0.0075i=

12

0.09

=0.0075

Time n=36 month

Now, put all the values we get,

D=\frac{1-(1+i)^{-n}}{i}D=

i

1−(1+i)

−n

D=\frac{1-(1+0.0075)^{-36}}{0.0075}D=

0.0075

1−(1+0.0075)

−36

D=\frac{1-(1.0075)^{-36}}{0.0075}D=

0.0075

1−(1.0075)

−36

D=\frac{0.2358}{0.0075}D=

0.0075

0.2358

D=31.44D=31.44

Monthly payment, M=\frac{\text{Amount}}{\text{Discount factor}}M=

Discount factor

Amount

M=\frac{23062.5}{31.44}M=

31.44

23062.5

M=733.38M=733.38

Monthly payment is $733.38

For 36 months the payment is 733.38\times 36=26401.68733.38×36=26401.68

Licence = $26401.68

The total purchase price of the car including tax, license, and title

Total purchase = 1921.875 +1921.875+175.13 +$26401.68

Total purchase = $28498.685

1 dollar = 100 cent

$28498.685 = 2849868.5 cent.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Two cars leave Phoenix and travel along roads 90 degrees apart. If Car 1 leaves 30 minutes earlier than Car 2 and averages 42 mp

romanna [79]

Answer:

C. 210 miles

Step-by-step explanation:

We have been given that two cars leave Phoenix and travel along roads 90 degrees apart. Car 1 leaves 30 minutes earlier than Car 2 and averages 42 mph.

We will use distance formula and Pythagoras theorem to solve our given problem.

$\text{Distance}=\text{Speed}\times \text{Time}$

$\text{Distance covered by Car 1 in 3.5 hours}=\frac{42\text{ Miles}}{\text{Hour}}\times \text{3.5 hour}$

$\text{Distance covered by Car 1 in 3.5 hours}=147\text{ Miles}$ .

Since car 1 leaves 30 minutes before car 2, so car 2 will travel for only 3 hours when car 1 will travel for 3.5 hours.

$\text{Distance covered by Car 2 in 3 hours}=\frac{50\text{ Miles}}{\text{Hour}}\times \text{3 hour}$

$\text{Distance covered by Car 2 in 3 hours}=150\text{ Miles}$

Since both car travel along roads 90 degree apart, therefore, the distance between both cars after Car 1 has traveled 3.5 hours would be hypotenuse with legs 147 and 150.

$\text{Distance between both cars}=\sqrt{147^2+150^2}$