Answer:
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Step-by-step explanation:
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Answer: the tuition in 2020 is $502300
Step-by-step explanation:
The annual tuition at a specific college was $20,500 in 2000, and $45,4120 in 2018. Let us assume that the rate of increase is linear. Therefore, the fees in increasing in an arithmetic progression.
The formula for determining the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = $20500
The fee in 2018 is the 19th term of the sequence. Therefore,
T19 = $45,4120
n = 19
Therefore,
454120 = 20500 + (19 - 1) d
454120 - 20500 = 19d
18d = 433620
d = 24090
Therefore, an
equation that can be used to find the tuition y for x years after 2000 is
y = 20500 + 24090(x - 1)
Therefore, at 2020,
n = 21
y = 20500 + 24090(21 - 1)
y = 20500 + 481800
y = $502300
It's a slope-intercept form where a slope = -1.5 and y-intercept = 3.
x - intercept: y = 0
Therefore we have the equation:
-1.5x + 3 = 0 |-3
-1.5x = -3 |:(-1.5)
x = 2
Answer: x-intercept = 2, y-intercept = 3
524 cm cubed
Explanation: 4/3 x pi x 5cubed = 523.599cm cubed rounded to 524cm cubed
