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malfutka [58]
3 years ago
11

Determine which postulate or theorem can be used to prove that ALMN =NOL​

Mathematics
1 answer:
ohaa [14]3 years ago
8 0
A. SSS


MRENU MEMNMUEEMEHMEK
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4 % of blank days is 56 days
klasskru [66]
We have an equation: 56/? = 4/100

Cross multiply:
4*? = 56*100
⇒ ? = 56*100/4 = 1,400

There are 1,400 blank days~
8 0
3 years ago
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What is the area of the regular pentagon below?
wolverine [178]

Answer:

<em><u>2</u></em><em><u>1</u></em><em><u>y</u></em><em><u>d</u></em><em><u>^</u></em><em><u>2</u></em>

Step-by-step explanation:

join the centre to all the vertex,

since this figure is of regular pentagon, it's will form 5 equal triangle of equal area!

now area of one such triangle is

1/2 ×base ×height

=1/2 ×3.5x2.4 (yd^2)

=4.2 yd^2

now the pentagon is sum of 5 such equal triangle,so it's are will be

5×4.2 (yd^2)

=21 yd^2

✌️:)

7 0
3 years ago
What’s 45 in scientific notation
Mashcka [7]

Answer

is 45 written as 4.5 x 101 in scientific notation

Step-by-step explanation:

Can i Be mark as the brainliest answer PLEASE!

8 0
3 years ago
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A rectangular picture frame has side lengths of 12 in by 9.5 in what is the length of the diagonal of the picture
OleMash [197]

Answer:

Length of diagonal of picture = 15.30 inches

Step-by-step explanation:

Given that:

Side lengths of picture frame = 12 inches by 9.5 inches

As the picture is rectangular, the diagonal will form hypotenuse of right angled triangle.

Using Pythagorean theorem;

a²+b²=c²

Putting the values in the theorem

(12)^2 + (9.5)^2 = c^2 \\144+90.25=c^2\\c^2 = 234.25

Taking square root on both sides

\sqrt{c^2}=\sqrt{234.25}\\c=15.30

Hence,

Length of diagonal of picture = 15.30 inches

3 0
3 years ago
JKLM is a rhombus. KM is 6 and JL is 8. Find the perimeter of the rhombus. image of rhombus JKLM with diagonals JL and KM inters
VLD [36.1K]
If a quadrilateral is a rhombus then:

i) all its sides have equal length,

and

ii) the 2 diagonals are perpendicular and bisect each other.


The 2 diagonals of rhombus JKLM intersect at N.

Then m(MNJ)=90°,  |JN|=4 and |NM|=3 units

thus, by the Pythagorean theorem, 

|MJ|= \sqrt{ 3^{2} + 4^{2} }= \sqrt{9+16}= \sqrt{25}=5

The perimeter of the rhombus is 4*5 units=20 units.


Answer: 20 units 

4 0
3 years ago
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