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alexdok [17]
2 years ago
9

-picture linked- ILL MARK BRAINLIEST PLEASE HELP ME ASAP

Mathematics
1 answer:
tatyana61 [14]2 years ago
6 0

Answer:

a

Step-by-step explanation:

You might be interested in
Ingnore question 17 but i need help 30 POINTS!!!
algol [13]
Not sure why they put the x bit

ok so know this:
AGE=HGB=CHG=FHD
and
AGH=EGB=CHF=GHD
and
AGE+AGH=180


11.
AGE=FHD=30

12.
AGH=CHF=150

13.
CHF=BGE=110

14.
CHG+HGA=180
CHG+120=180
CHG=60

15.
BHG=3x=AGE=CHG=FHD
not sure, but if we did use the fact that BGH+DHG=180 and BGH=3x and DHG=2x+50 then BHG=78 degrees

16.
GHD=2x+50=CHF=EGB=AGH, if we use facts above then GHD=102 degrees
5 0
3 years ago
Assume that adults have iq scores that are normally distributed with a mean of 100100 and a standard deviation of 15. find the t
anastassius [24]
The bell curve attached below shows the normal distribution of the data.

We are looking the value of X such as the area to its left gives the probability of 0.75

We first need the z-score which we can obtain by reading from the z-table (as shown in the second picture below)

The z-score is = 0.7734

Then we use the following formula to work out X
z-score = (X - Mean) ÷ Standard Deviation
0.7734 = (X - 100) ÷ 15
0.7734×15 = X - 100
11.601 = X - 100
X = 11.601 + 100
X = 111.601 ≈ 112 

Hence the third quartile is 112

4 0
2 years ago
Cos 0=9/15 find tan 0
Liula [17]

Answer:

I HAVE NO CLUE BUT HAVE A NICE DAY....

5 0
2 years ago
The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 101010 denarii per day to support 444
givi [52]

<u>the correct question is</u>

The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 10 denarii per day to support 4 legionaries and 4 archers. It only costs 5 denarii per day to support 2 legionaries and 2 archers. Use a system of linear equations in two variables. Can we solve for a unique cost for each soldier?

Let

x-------> the cost to support a legionary per day

y-------> the cost to support an archer per day

we know that

4x+4y=10 ---------> equation 1

2x+2y=5 ---------> equation 2

If you multiply equation 1 by 2

2*(2x+2y)=2*5-----------> 4x+4y=10

so

equation 1 and equation 2 are the same

The system has infinite solutions-------> Is a consistent dependent system

therefore

<u>the answer is</u>

We cannot solve for a unique cost for each soldier, because there are infinite solutions.

5 0
2 years ago
Consider the system:
Gnom [1K]

Answer:

Step-by-step explanation:

In this problem, we have the following linear equations:

y=3x+5

y=ax+b

We know that a linear equation is an equation for a line. In a system of linear equations, two or more equations work together.

1.  What values for a and b make the system inconsistent?

A system is inconsistent if and only if the lines are parallel in which case the system has no solution. This is illustrated in the first Figure bellow. Two lines are parallel if they share the same slope. So, the system is inconsistent for:

a=3

for any value of b

2. What values for a and b make the system consistent and dependent?

A system is consistent if and only if the lines are the same in which case the system has infinitely many solutions. This is illustrated in the second Figure bellow. So, the system is consistent and dependent for:

a=3 and b=5

8 0
2 years ago
Read 2 more answers
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