Question

Triangle PQR is formed by the three squares A, B, and C:

Answer 1

Answer:

A.$PR^2=PQ^2+QR^2$

Because $25=9+16$

Step-by-step explanation:

We are given that

Area of square A=$9$ square units

Are of square B=$16$ square units

Area of square C=$25$ square units

We have to find the relationship between sides of triangle PQR.

Side of square=$\sqrt{Area\;of\;square}$

Using the formula

Side of square A=$\sqrt{9}$=3 units

Side of square B=$\sqrt{16}=4$ units

Side of square C=$\sqrt{25}=5$ units

Pythagoras theorem

$(hypotenuse)^2=(Base)^2+(Perpendicular\;side)^2$

Using Pythagoras theorem

$PR^2=PQ^2+QR^2$

$5^2=3^2+4^2$

$25=9+16$

Option A is true

Answer 2

The first choice if ()2 means to the power of two if not then it is none of them.