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3 years ago

Please answer both questions Thankyou

Chemistry

1 answer:

erma4kov [3.2K]3 years ago

7 0

Answer:

The limiting reactant is oxygen gas and the reaction would produce 3.932 x 10 ^ 7 moles of water

Explanation:

Step 1: Convert everything into moles

nH2(l) = 1.06 x 10^8 g / 2.016 g/mol = 5.26 x 10^7 mols

nO2(l) = 6.29 x 10^8 g / 32.00 g/ mol = 1.966 x 10^7 mols

Step 2: Find the limiting reagent

The limiting reagent would be oxygen gas from

the balanced equation because we have less moles of oxygen gas needed to fully combust with the hydrant gas

Step 3: Stoichiometry time

The mole ratio from oxygen gas to water is 1:2

This means that for every mole of oxygen gas two moles of water is produced

We need to multiply the moles of oxygen gas by two to find out how many moles of water has been produced

nH2O = nO2 x 2

nH2O = 1.966x10^7 x 2

nH2O = 3.932x10^7

Step 4: Therefore statement

Therefore the limiting reactant is oxygen gas and the reaction would produce 3.932 x 10 ^ 7 moles of water

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The following anions can be separated by precipitation as silver salts: Cl- , Br- , I- , CrO4 2-. If Ag is added to a solution c

dalvyx [7]

Answer:

AgI, AgBr, AgCl and Ag₂CrO₄

Explanation:

Ksp (product solubility constant) is defined as the equilibrium constant of the general reaction:

XₐYₙ(s) → aXⁿ⁺(aq) + nYᵃ⁻(aq)

Where X is cation and Y is anion.

Ksp = [aXⁿ⁺]ᵃ [nYᵃ⁻]ⁿ

The presence of XₐYₙ(s) produce ax moles of aXⁿ⁺ and nx moles of Yᵃ⁻. Where X is the solubility of the compound.

Replacing in Ksp:

Ksp = [ax]ᵃ [nx]ⁿ

Solving for x, Solubility (S) is defined as:

$S = \sqrt[n+a]{\frac{Ksp}{a^{a} n^n} }$

For AgCl, Ag₂CrO₄, AgBr and AgI solubilities are:

$S = \sqrt[2]{\frac{1.8x10^{-10}}{1} }$ = 1.34x10⁻⁵M

$S = \sqrt[3]{\frac{1.1x10^{-12}}{4} }$ = 6.50x10⁻⁵M

$S = \sqrt[2]{\frac{5.4x10^{-13}}{1} }$ = 7.35x10⁻⁷M

$S = \sqrt[2]{\frac{8.5^{-17}}{1} }$ = 9.22x10⁻⁹M

The lower solubility is the first compound in precipitate, thus, order of precipitation is:

AgI, AgBr, AgCl and Ag₂CrO₄

8 0

3 years ago

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Goryan [66]

Answer:

Explanation:

because it has gained an electron

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3 years ago

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OLEGan [10]

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3 years ago

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drek231 [11]

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6 0

2 years ago

Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 2.10 g of ethane is

puteri [66]

Answer:

Ethane is the limiting reactant, so no mass of ethane will be left over by the chemical reaction. All the mass will react, the 2.1 grams of ethane.

Explanation:

First of all, we need to determine the reaction and the limiting reactant to work with the stoichiometry.

The equation is: 2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O

We define the moles of the reactants:

2.10 g / 30 g/mol = 0.07 moles of ethane

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To determine the limiting reactant, we start with oxygen:

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7 0

3 years ago

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