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____ [38]
3 years ago
9

How many atoms of fluorine are in 5.6x10^22 molecules of MgF2.

Chemistry
1 answer:
Serhud [2]3 years ago
7 0

Answer:

1.12 x 10²³atoms of F

Explanation:

Number of MgF₂ atoms = 5.6 x 10²² molecules;

 The unknown here is the number of Fluorine atoms found in the compound.

In MgF₂,

     1 mole of MgF₂ contains 2 moles of F;

From the given number of molecules we can also say that, MgF₂ contains 5.6 x 10²²atoms;

           1 mole of MgF₂ contains 2 moles of F;

    5.6 x 10²²atoms of MgF₂ will contain 2 x   5.6 x 10²² = 1.12 x 10²³atoms of F

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<h3>General Formulas and Concepts:</h3>

<u>Math</u>

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<u>Step 1: Define</u>

85 g AgNO₃ (silver nitrate)

<u>Step 2: Identify Conversions</u>

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<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 85 \ g \ AgNO_3(\frac{1 \ mol \ AgNO_3}{169.88 \ g \ AgNO_3})(\frac{6.022 \cdot 10^{23} \ molecules \ AgNO_3}{1 \ mol \ AgNO_3})
  2. Multiply/Divide:                                                                                                \displaystyle 3.01313 \cdot 10^{23} \ molecules \ AgNO_3

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

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