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levacccp [35]
2 years ago
11

Aqueous lead (II) nitrate, Pb(NO3)2 undergoes a double displacement reaction with aqueous sodium chloride, NaCl, in which a prec

ipitate forms. If the precipitate contains lead, write the balanced chemical equation for this reaction. Be sure to include the states of each of the reactants and products
Chemistry
1 answer:
Dvinal [7]2 years ago
8 0

Answer:

{ \sf{Pb(NO_{3})_{2(aq)}  + 2NaCl _{(aq)} → 2NaNO_{3(aq)}  + PbCl _{2(s)} }} \\

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Please help!! Balancing Nuclear Equations
sineoko [7]

The missing part of the equation is found to be 4/2He. Option A

<h3>What are nuclear equations?</h3>

The term nuclear equations have to do with the type of equation in which one type of nucleus is transformed into another sometimes by the bombardment or loss of a particle.

Now the full equation ought to be written as 7/3Li + 1/1H -----> 4/2He + 4/2He. This is because the total mass on the left is 8 and the total charge on the left is 4.

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8 0
2 years ago
In a simple covalent compound, which statement is TRUE
Savatey [412]

Answer:

C:to the right side of the periodic table, and it is given

the suffix -ide.

5 0
2 years ago
What particles form the nucleus of an atoms?
melomori [17]

Answer:

Protons and neutrons

Explanation:

The particles to forms the nucleus of an atom are the protons and neutrons of the atoms.

These materials are located in the tiny nucleus and contributes the most mass of the atom.

  • Protons are the positively charged particles in an atom
  • Neutrons do not carry any charges.
  • Sum of the protons and neutrons gives the mass number of the atom.
7 0
2 years ago
A certain radioactive nuclide has a half life of 1.00 hour(s). Calculate the rate constant for this nuclide. s-1 Calculate the d
Karo-lina-s [1.5K]

Answer:

k= 1.925×10^-4 s^-1

1.2 ×10^20 atoms/s

Explanation:

From the information provided;

t1/2=Half life= 1.00 hour or 3600 seconds

Then;

t1/2= 0.693/k

Where k= rate constant

k= 0.693/t1/2 = 0.693/3600

k= 1.925×10^-4 s^-1

Since 1 mole of the nuclide contains 6.02×10^23 atoms

Rate of decay= rate constant × number of atoms

Rate of decay = 1.925×10^-4 s^-1 ×6.02×10^23 atoms

Rate of decay= 1.2 ×10^20 atoms/s

8 0
3 years ago
Classify the species given below by the intermolecular forces present in a pure sample of each
Katarina [22]
Hydrogen bonds are present in the following molecules: HF AND NH3  
Dipole dipole inter molecular forces occurs the molecules of H2S  AND H2.
Hydrogen bonding is an electrostatic attraction between two polar groups that occur when hydrogen atom covalently bound with highly electronegative atoms.
3 0
3 years ago
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