Answer:
One example of a medium is air.
Explanation:
Answer:
7.5 × 10^9 J.
Explanation:
So, we are given the following data or parameters or information for the proper solving of the question above;
=> ''actual force exerted by the tractor beam as a function of position is given by F(x) = ax + , where a = 6.1 x 10 N/mº and B = -4.1 x 10° N''
=> " Assume the supply spacecraft had an initial kinetic energy of KE = 2.7 x 10" J "
=> "that the tractor beam force is applied on the spacecraft over a distance of 7.5 x 10^11 m away.from its beginning position at = 0.0 m"
So, we can then solve it as;
KE2 – KE1 = F(x) dr.
KE2 - 2.7 x 10^11 J = - 3.5 × 10^6 × 7.5 x 10^4.
KE2 = 7.5 × 10^9 J.
Answer:
vx = 65 yd/3 sec = 21.7 yd/sec since horizontal speed is constant
vy = g t = (32 / 3) yd/sec^2 * 1.5 sec = 16 yd/sec where 32/3 is the acceleration due to gravity in yds / sec^2 and 1.5 is the time to travel each way in the vertical direction
V = (vx^2 + vy^2)^1/2 = (21.7^2 + 16^2)^1/2 = 27 yd/sec
tan theta = vy/vx = 16 / 21.7 = .737 theta = 36.4 deg
You can check using the range formula:
R = v^2 sin (2 theta) / g = 27^2 * .955 / (32 / 3) = 65.3 yds
The difference from 65 yds may be rounding error.
The net force on the car for either case will be zero, since the car is moving at a constant velocity.
<h3>Net force on the car</h3>
The net force on the car is the sum of all the forces acting on the car.
∑F = ma
<h3>When the car is on a level road</h3>
When the car is on a level road, the only two forces acting on the car is the applied force and frictional force of the road.
F - Ff = 0
The net force will be zero, since the car is moving at a constant velocity.
<h3>When the car is on uphill</h3>
The forces acting on the car at the uphill is the applied force, weight of the car acting downwards and the frictional force acting opposite direction.
F - Wsinθ - μFₙcosθ = 0
The net force will be zero, since the car is moving at a constant velocity.
Learn more about net force at constant velocity here: brainly.com/question/14392124
The force of gravity and the force of air