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bija089 [108]
3 years ago
6

The force of Earth's gravity pulls down on a stone after someone tosses it off a cliff. What is the "equal and opposite force" d

uring this interaction, according to Newton's third law?
Physics
1 answer:
Lapatulllka [165]3 years ago
3 0

The equal and opposite force is the force of the stone's gravity pulling up on thy Earth.

<u>Explanation</u>:

                                      F_{AB} = - F_{BA}

  • When someone tosses a stone off a cliff, the force of gravity of Earth pulls down and the force of the stone's gravity pulls up on the Earth due to the equal and opposite reaction exerted between the Earth and the stone.
  • In Newton's third law, two important features are present. One is the force exerted on two bodies will have the same magnitude but opposite direction. The other feature is force is acting on two different objects.
  • This exerted force is equal in magnitude but opposite in direction whereas the gravity exerts a downward force on a stone and upward force on an Earth which is opposite in direction.

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. A car with a mass of 700-kg changes its speed from 10.0 m/s to 30.0 m/s in a displacement of 50.0 meters. Calculate the net fo
Nezavi [6.7K]

Answer:

5600N

Explanation:

Given parameters:

Mass of car  = 700kg

Initial velocity  = 10m/s

Final velocity  = 30m/s

Displacement  = 50m

Unknown:

Net force acting on the car  = ?

Solution:

To find the force acting on a body, it is pertinent we know the mass and acceleration.

 Force  = mass x acceleration

Now;

 Let us find the acceleration from the kinematics equations:

 v²  = u²  + 2aS

 v is the final velocity

 u is the initial velocity

 a is the acceleration

 S is the distance

  30²  = 10²  + (2 x a x 50)

 900 = 100 + 100a

      100a  = 800

           a  = 8m/s²

Therefore;

     Force  = 700 x 8  = 5600N

6 0
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