Answer:
d) 1.2 mT
Explanation:
Here we want to find the magnitude of the magnetic field at a distance of 2.5 mm from the axis of the coaxial cable.
First of all, we observe that:
- The internal cylindrical conductor of radius 2 mm can be treated as a conductive wire placed at the axis of the cable, since here we are analyzing the field outside the radius of the conductor. The current flowing in this conductor is
I = 15 A
- The external conductor, of radius between 3 mm and 3.5 mm, does not contribute to the field at r = 2.5 mm, since 2.5 mm is situated before the inner shell of the conductor (at 3 mm).
Therefore, the net magnetic field is just given by the internal conductor. The magnetic field produced by a wire is given by

where
is the vacuum permeability
I = 15 A is the current in the conductor
r = 2.5 mm = 0.0025 m is the distance from the axis at which we want to calculate the field
Substituting, we find:

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The answer is destructive interference. You have this for both C and D. I suspect one of C or D is supposed to be constructive interference... But destructive interference is the answer
According to the conservation of energy
- Potential energy at any given instance is equal to the Kinetic energy as energy can neither be created nor be destroyed
Mass is 2kg=m
#A
h=5m
PE
Now
- KE=98J
- 1/2mv²=98J
- 1/2×2v²=98J
- v²=98J
- v=√98
- v=9.4m/s
#B
h=3.2m
PE:-
Now
- KE=62.7J
- 1/2mv²=62.7
- v²=62.7
- v=√62.7
- v=7.9m/s
#C
h=2m
PE
Now