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Gre4nikov [31]
3 years ago
12

Which of these processes of the water cycle is a direct effect of the sun's energy?

Physics
2 answers:
Slav-nsk [51]3 years ago
8 0
<span>a. evaporation

Hope it helps!
</span>
Artyom0805 [142]3 years ago
7 0

Answer:

Option a) Evaporation

Explanation:

Option b) seeping of water into soil is the process by which water on the surface of earth enters soil inside earth slowly

c) formation of precipitation are developed in clouds, and clouds are formed when water vapor in the atmosphere cools and condenses. Hence cannot be direct effect of Sun energy

d) runoff of water from soil is the flow water when excess water due to flood is there, which causes soil erosion.

But our question of a direct effect of the Sun's energy is option a) evaporation.

By evaporation, we see that floor with water dry, clothes washed when put to dry dries, etc.

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Which of the examples below is an example of convection?
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Basking in the sun :)
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3 years ago
20 points ! Help!!! Please and thank you !
Delvig [45]

Number 7is 64. 8 is 486 because 3 to the 5th is 243 then multiply by 2.

9 is 1003.092

10. Is 5

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4 years ago
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In what way does ocean water move globally? A. Along cold-water currents from the Poles to the equator B. From the cold Western
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3 years ago
A mail carrier leaves the post office and drives 2.00 km to the north. He then drives in a direction 60.0° south of east for 7.00
Oxana [17]

Answer:

12.97 km

Explanation:

In order to find the resultant displacement, we have to resolve each of the 3 displacements along the x and y direction.

Taking north as positive y direction and east as positive x-direction, we have:

- Displacement 1: 2.00 km to the north

So

A_x = 0\\A_y = +2.00 km

- Displacement 2: 60.0° south of east for 7.00 km

So

B_x=(7.00)(cos (-45^{\circ}))=4.95 km\\B_y = (7.00)(sin (-45^{\circ}))=-4.95 km

- Displacement 3: 9.50 km 35.0° north of east

So

C_x=(9.50)(cos 35^{\circ})=7.78 km\\C_y=(9.50)(sin 35^{\circ})=5.45 km

So the net displacement along the two directions is:

R_x=A_x+B_x+C_x=0+4.95+7.78=12.73 km\\R_y=A_y+B_y+C_y=2.00+(-4.95)+5.45=2.50 km

So, the  distance between the initial and final position is equal to the magnitude of the net displacement:

R=\sqrt{R_x^2+R_y^2}=\sqrt{12.73^2+2.50^2}=12.97 km

7 0
3 years ago
The half-life of carbon-14 is 5370 years. The carbon-14 levels in a fossil indicate that 6 half-lives have passed. How old is th
vodomira [7]
On half life is 5370 years; 6 half lives have passed. You just multiply,

5370*6 = 32,220 years
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