The answer is 14 because 56 divided by 4
We have this equation:
First, combine both logarithms using the multiplication property and simplify the expression.
![\log[x(x + 99)] = 2](https://tex.z-dn.net/?f=%5Clog%5Bx%28x%20%2B%2099%29%5D%20%3D%202)
![\log[ {x}^{2} + 99x ] = 2](https://tex.z-dn.net/?f=%5Clog%5B%20%7Bx%7D%5E%7B2%7D%20%2B%2099x%20%5D%20%3D%202)
Now, use the definition of logarithm to transform the equation.
Finally, use the quadratic formula to solve the equation.
With this, we can say that the solution set is:
We cannot choose x = -100 as a solution because we cannot have a negative logarithm. The only solution is x = 1.
Intersecting the x axis means y is 0
plug y=0 in the equation and solve for x to see if there are real solutions
x^2-10x+0+0=-30
x^2-10x+30=0
this cannot be factored, so let's see if b^2-4ac is bigger than 0
10^2-4*1*30=-20
so the solutions for this equation are not real numbers, therefore the answer is no.
The factored expression of m(2a+b)-n(2a+b)+2n(2a+b) is (m + n)(2a + b)
<h3>How to factor the expression?</h3>
The expression is given as:
m(2a+b)-n(2a+b)+2n(2a+b)
Factor out 2a + b
m(2a+b)-n(2a+b)+2n(2a+b) = (m - n + 2n)(2a + b)
Evaluate the like terms
m(2a+b)-n(2a+b)+2n(2a+b) = (m + n)(2a + b)
Hence, the factored expression of m(2a+b)-n(2a+b)+2n(2a+b) is (m + n)(2a + b)
Read more about factored expressions at:
brainly.com/question/723406
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