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2 years ago

9/8 divided by 3/8 3/5 divided by 2/3

1 answer:

8 0

9/8 divided by 3/8 is 3 (because of the same denominator look at the first number)

3/5 divided by 2/3 is 0.9 hope this helps

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How would you scale down by a factor of 1/10?

slavikrds [6]

Answer:

See example below.

Step-by-step explanation:

To scale down by a factor of 1/10, multiply the side length or distance by 1/10.

Example:

If the distance was 5 then 5*1/10 = 5/10 = 1/2 is the scaled down version.

6 0

3 years ago

I'm having trouble with this

tester [92]

The answer is 9

mark brainliest

4 0

3 years ago

Every third visitors to a museum gets a free bumper sticker. Every fifth visitor to that museum gets a free key chain. Which vis

Rashid [163]

The fifteenth customer will be the first because 5x3=15

8 0

3 years ago

Let f(x) = 2x – 1, g(x) = 3x, and h(x) = x2 + 1. Compute the following.

bonufazy [111]

4.
h(f(x)=h(2x-1)=
(2x-1)^2+1=
4x²-4x+1+1=
4x²-4x+2

5.
f(f(x))=2(2x-1)-1=4x-2-1=4x-3

6.
f o g (x)=f(g(x))
h o g (x)=h(g(x))=
(3x)^2+1=
9x²+1

4 0

3 years ago

In how many ways can 6 competitors finish a race assuming there are no ties?In how many ways can we sit n people on r < n cha

VLD [36.1K]

Answer: a) 720, b) $^nC_r=\dfrac{n!}{(n-r)!r!}$ c) 336, d) 30240 e) 120.

Step-by-step explanation:

Since we have given that

a) Number of competitors = 6

We need to find the number of ways that 6 competitors can finish a race and there are no ties.

So, Number of ways would be

$6!=720$

b) number of people = n

Number of chairs = r (r<n)

so, the number of ways we can sit n people on r<n chairs is given by

$^nC_r=\dfrac{n!}{(n-r)!r!}$

c) If there are three awards :

Gold, silver, bronze.

We need to find the number of ways that these medals can be awarded.

Number of ways is given by

$^8P_3\\\\=336$

d) Number of 5-digit zip codes are possible is given by

$^{10}P_5=30240$

e) Number of poeple = 10

Number of people required in committee = 3

Number of different 3 person committee that are selected from 10 people is given by

$^{10}C_3=120$

Hence, a) 720, b) $^nC_r=\dfrac{n!}{(n-r)!r!}$ c) 336, d) 30240 e) 120.

6 0

3 years ago