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3 years ago

What is the solution to the inequality 75 greater-than StartFraction x over 15 EndFraction?

Mathematics

2 answers:

Leto [7]3 years ago

5 0

Answer:

Step-by-step explanation:

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Vesnalui [34]3 years ago

4 0

Answer:

Step-by-step explanation:

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A store owner makes a profit of $54 when he sells 9 jackets.How many jackets should he sell to make a profit of $270? jackets

Goryan [66]

First you have to find the cost of each jacket.
54/9=6 Each jacket cost $6
Then you get the total profit and divide that by the cost of each jacket.
270/6=45 (45 jackets)
Multiply 45 jackets by the cost ($6)
45*6=$270.
The answer is 45.

3 0

4 years ago

A well known pharmaceutical manufacturer is manufacturing a newly developed vaccine, and is concerned about variability in the i

Lana71 [14]

Answer:

The null hypothesis is $H_o : \ \sigma^2 = 1.9$

The alternative hypothesis is $H_a : \ \sigma^2 \ne 1.9$

$X^2 = 13.74$

The decision rule is

Reject the null hypothesis

The conclusion is

There is no sufficient evidence to conclude that the variance of the immune response is equal to 1.9.

Step-by-step explanation:

From the question we are are told that

The variance is $\sigma ^2 = 1.9$

The sample size is n = 30

The sample variance is $s^2 = 0.9$

The level of significance is $\alpha = 0.05$

The null hypothesis is $H_o : \ \sigma^2 = 1.9$

The alternative hypothesis is $H_a : \ \sigma^2 \ne 1.9$

Generally the test statistics is mathematically represented as

$X^2 = \frac{ (n- 1 ) * s^2 }{ \sigma^2 }$

=> $X^2 = \frac{ (30 - 1 ) * 0.9 }{1.9 }$

=> $X^2 = 13.74$

Generally from the degree of freedom is mathematically represented as

$df = n- 1$

=> $df = 30 - 1$

=> $df = 29$

Generally from the chi distribution table the critical value of $\frac{\alpha}{2} \ and \ 1 - \frac{ \alpha }{2}$ at a degree of freedom of $df = 29$ is