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Mandarinka [93]
3 years ago
10

FITT Principle overdue test questions for PE/Wellness. I get two chances and the highest score is the attempt that will be recor

ded.

Physics
2 answers:
saveliy_v [14]3 years ago
8 0
Last option.............
adoni [48]3 years ago
7 0

Answer: The las option

Explanation:

it is the last option because the FITT principal stands for frequency

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Using a refracting telescope, you observe the planet Mars when it is 2.11 × 10 11 m 2.11×1011 m from Earth. The diameter of the
Norma-Jean [14]

Answer:

y = 150 Km

Explanation:

given,                                                      

Distance of the planet Mars from earth D = 2.11 × 10¹¹ m          

The diameter of the telescope's objective lens d = 0.949 m      

The wavelength of light λ = 553 nm            

                                        = 553 x 10⁻⁹ m            

resolution of the telescope = ?                          

     y = \dfrac{1.22\lambda\ D}{d}          

     y = \dfrac{1.22\times 553\times 10^{-9}\times 2.11 \times 10^{11}}{0.949}                                          

           y = 150003 m                          

          y = 150 Km                          

the minimum feature size is equal to y = 150 Km

8 0
3 years ago
At a time t = 2.80 s , a point on the rim of a wheel with a radius of 0.230 m has a tangential speed of 51.0 m/s as the wheel sl
bonufazy [111]

Answer:

Part A) the angular acceleration is α= 44.347 rad/s²

Part B) the angular velocity is 195.13 rad/s

Part C)  the angular velocity is 345.913 rad/s

Part D ) the time is t= 7.652 s

Explanation:

Part A) since angular acceleration is related with angular acceleration through:

α = a/R = 10.2 m/s² / 0.23 m =   44.347 rad/s²

Part B) since angular acceleration is related

since

v = v0 + a*(t-t0) =  51.0 m/s + (-10.2 m/s²)*(3.4 s - 2.8 s) = 44.88 m/s

since

ω = v/R = 44.88 m/s/ 0.230 m = 195.13 rad/s

Part C) at t=0

v = v0 + a*(t-t0) =  51.0 m/s + (-10.2 m/s²)*(0 s - 2.8 s) = 79.56 m/s

ω = v/R = 79.56 m/s/ 0.230 m = 345.913 rad/s

Part D ) since the radial acceleration is related with the velocity through

ar = v² / R → v= √(R * ar) = √(0.23 m  * 9.81 m/s²)= 1.5 m/s

therefore

v = v0 + a*(t-t0) → t =(v -  v0) /a + t0 = ( 1.5 m/s - 51.0 m/s) / (-10.2 m/s²) + 2.8 s = 7.652 s

t= 7.652 s

4 0
3 years ago
The unit of mass is fundamental unit​
Irina18 [472]

Answer:

Kilogram and symbol kg.

7 0
3 years ago
Read 2 more answers
Three polarizing filters are stacked, with the polarizing axis of the second and third filters at angles of 23.8 ∘ and 65.0 ∘, r
GalinKa [24]

Hey! How are you? My name is Maria, 19 years old. Yesterday broke up with a guy, looking for casual sex.

Write me here and I will give you my phone number - *pofsex.com*

My nickname - Lovely

4 0
4 years ago
A 42.0-kg parachutist is moving straight downward with a speed of 3.85 m/s. (a) If the parachutist comes to rest with constant a
RideAnS [48]

Answer:

-414.96 N

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-3.85^2}{2\times 0.75}\\\Rightarrow a=-9.88\ m/s^2

F=ma\\\Rightarrow F=42\times -9.88\\\Rightarrow F=-414.96\ N

The force the ground exerts on the parachutist is -414.96 N

If the distance is shorter than 0.75 m then the acceleration will increase causing the force to increase

5 0
3 years ago
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