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AlladinOne [14]
3 years ago
14

Using a refracting telescope, you observe the planet Mars when it is 2.11 × 10 11 m 2.11×1011 m from Earth. The diameter of the

telescope's objective lens is 0.949 m 0.949 m . What is the minimum feature size, in kilometers, on the surface of Mars that your telescope can resolve for you? Use 553 nm 553 nm for the wavelength of light.
Physics
1 answer:
Norma-Jean [14]3 years ago
8 0

Answer:

y = 150 Km

Explanation:

given,                                                      

Distance of the planet Mars from earth D = 2.11 × 10¹¹ m          

The diameter of the telescope's objective lens d = 0.949 m      

The wavelength of light λ = 553 nm            

                                        = 553 x 10⁻⁹ m            

resolution of the telescope = ?                          

     y = \dfrac{1.22\lambda\ D}{d}          

     y = \dfrac{1.22\times 553\times 10^{-9}\times 2.11 \times 10^{11}}{0.949}                                          

           y = 150003 m                          

          y = 150 Km                          

the minimum feature size is equal to y = 150 Km

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28.81 m

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6 0
3 years ago
Two identical loudspeakers are placed on a wall 1.00 m apart. A listener stands 4.00 m from the wall directly in front of one of
natita [175]

Answer:

The phase difference is 0.659 rad.

Explanation:

Given that,

Distance between two identical loudspeakers d= 1.00  m

Distance between speakers and listener r= 4.00 m

Frequency = 300 Hz

Suppose we need to find the phase difference in radian between the waves from the speakers when they reach the observer

We need to calculate the r'

Using Pythagorean theorem

r'=\sqrt{d^2+r^2}

Where, d = distance between two identical loudspeakers

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r'=\sqrt{(1.00)^2+(4.00)^2}

r'=\sqrt{1.00+16.00}

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Using formula of path difference

|r'-r|=4.12-4.00

|r'-r|=0.12\ m

We need to calculate the wavelength

Using formula of wavelength

\lambda=\dfrac{v}{f}

Where, v = speed of sound

f = frequency

Put the value into the formula

\lambda=\dfrac{343}{300}

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We need to calculate the phase difference

Using formula of phase difference

\phi=\dfrac{2\pi\times|r'-r| }{\lambda}

\phi=\dfrac{2\pi\times0.12}{1.143}

\phi=0.659\ rad

Hence, The phase difference is 0.659 rad.

7 0
3 years ago
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