The temperature outside a plane flying at an altitude of 5 kilometers is -17°C.
Given that,
- The ground temperature at the airport is 10 °C.
- The decrease in temperature is 5.4°C for each & every rise in 1 kilometer.
Based on the above information, the temperature outside should be
The decrease in the temperature should be
= 5.4×5
= 27°C
Now the final temperature is
= 10 - 27
= -17°C
Therefore we can conclude that the temperature outside a plane flying at an altitude of 5 kilometers is -17°C.
Learn more: brainly.com/question/20459283
We are tasked to solve the value of p(8a) in the expression p(x)=3x^2-4.
This means that what would find the value of the expression when x=8a. To solve this, we simply substitute the value of x in the expression.
p(x)=3x^2-4
p(8a)=3(8a)^2-4
p(8a)=3(64a^2)-4
p(8a)=192a^2-4
x=8+sqrt-8/12, x=8-sqrt-8/12
I think...
<span>Let A = the area of the whole circle
Let S = the area of the shaded portion</span><span>
The shaded area is a portion of the circle that is determined by the ratio of the shaded sector to the whole circle of 360 degrees, or
S = (60/360) </span>× <span>A = ( 1 / 6 ) </span>× 12 = 2 ;
Remember that the cone volume formula is 
, with r = radius and h = height. Using our information, we can form our equation as such: 
(I'll be keeping the answer in pi form.)
Firstly, solve the exponents:
Next, multiply 4 and 19/3 together and your answer should be (rounded to the hundreths): V = 25.33π un^3
