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NemiM [27]
3 years ago
15

5 - 3(6 - 2y)

Mathematics
2 answers:
saul85 [17]3 years ago
6 0

Answer:

6y - 13

Step-by-step explanation:

5 - 3(6 - 2y)

Distribute;

5 - 18 + 6y

-13 + 6y <em>OR</em> 6y - 13

AlexFokin [52]3 years ago
5 0
6y-13 hope this helps
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Find the product. (1.8 x 10^5)(3.1 x 10^2)
Stells [14]

Answer:

5.58*10^7

Step-by-step explanation:

Recall that 10^a*10^b = 10^(a+b).  Thus, 10^5*10^2 = 10^7.

Thus, (1.8 x 10^5)(3.1 x 10^2) = (1.8)(3.1)*10^7 = 5.58*10^7

                           

7 0
3 years ago
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Given that the hypotenuse of a triangle is c, which is the Pythagorean Theorem? a2 + c2 = b2 a2 – b2 = c2 2a + 2b = 2c none of t
Alexandra [31]
The pythagorean theorem states that a^2+ b^2=c^2.
Final answer: None of the above
6 0
3 years ago
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Question Completion Status:
jeka94

Answer:

y=3x-3

Step-by-step explanation:

The equation of the line with the slope m and passing through the point (x_0,y_0) is

y-y_0=m(x-x_0)

In your case,

m=3\\ \\x_0=3\\ \\y_0=6

Hence, the equation of the line is

y-6=3(x-3)\\ \\y-6=3x-9\\ \\y=3x-9+6\\ \\y=3x-3

3 0
3 years ago
PLEASE HELP!!!! WILL MARK BRAINLIEST!!!!
irga5000 [103]

Answer:

None of these.

Step-by-step explanation:

Let's assume we are trying to figure out if (x-6) is a factor. We got the quotient (x^2+6) and the remainder 13 according to the problem.  So we know (x-6) is not a factor because the remainder wasn't zero.

Let's assume we are trying to figure out if (x^2+6) is a factor.  The quotient is (x-6) and the remainder is 13 according to the problem.  So we know (x^2+6) is not a factor because the remainder wasn't zero.

In order for 13 to be a factor of P, all the terms of P must be divisible by 13.  That just means you can reduce it to a form that is not a fraction.

If we look at the first term x^3 and we divide it by 13 we get \frac{x^3}{13} we cannot reduce it so it is not a fraction so 13 is not a factor of P

None of these is the right option.

4 0
3 years ago
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What is -3m-8v-4m+5v
vladimir1956 [14]
I hope this helps you



-3m-4m-8v+5v


-7m-3v
3 0
3 years ago
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