Draw the major product formed when the given epoxide reacts with aqueous acid. Use wedge and dash bonds, including hydrogen atom
1 answer:
Answer:
See explanation
Explanation:
An epoxide is a heterocyclic organic compound that has oxygen as part of the ring.
The first step in this reaction is the opening of the ring by the protonation of the oxygen by the acid. This now creates a carbocation which is quickly attacked by a water molecule.
Loss of a proton yields the product and regenerates the acid catalyst
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Answer:
44,55 can be produced.
Explanation:
First, we balanced the equation
1Cu + 2AgNO3 → 1Cu(NO3)2 + Ag
Then, we find the moles of each reagent
Now, we find the limiting reagent from the quantities of product that can be formed from each reagent
1,086 moles of AgNO3 is necessary for each mole of Cu since we have 0.413 moles of Ag(NO3), the nitrate is the limiting reagent
the value of the limiting reagent determines the amount of product that is generated
∴ 0,413 mol of Ag can be produced
Ag = = 44,55g
Ag≈ 44,6g
Answer:
The mass percent of aluminum sulfate in the sample is 16.18%.
Explanation:
Mass of the sample = 1.45 g
Mass of the precipitate = 0.107 g
Moles of aluminum hydroxide =
According to reaction, 2 moles of aluminum hydroxide is obtained from 1 mole of aluminum sulfate .
Then 0.001372 moles of aluminum hydroxide will be obtained from:
Mass of 0.000686 moles of aluminum sulfate :
= 0.000686 mol × 342 g/mol = 0.2346 g
The mass percent of aluminum sulfate in the sample: