Question

Circle L is shown. Line segments K L and M L are radii. The length of K L is 12. Angle M L K is 60 degrees. Sector M L K with a 60 degree angle is shaded.
What is the area of the sector that is not shaded?


12Pi units squared

24Pi units squared

120Pi units squared

144Pi units squared

Answer 1

Answer:

$120\pi$ square units

Step-by-step explanation:

We are given that

Radius of circle=12 units

Angle MLK=60 degree

We have to find the area of sector that is not shaded.

Area of shaded sector MLK=$\frac{\theta}{360}\times \pi r^2$

Area of shaded sector MLK=$\frac{60}{360}\times \pi(12)^2=$24 square units

Area of whole circle=$\pi r^2=\pi (12)^2=144\pi$square units

Area of sector that is not shaded =Area of whole circle-Area of shaded sector MLK=$144\pi-24\pi$

Area of sector that is not shaded=$120\pi$ square units

Answer 2

Answer:

C

Step-by-step explanation:

edge