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alexdok [17]
2 years ago
7

If the diameter of a sphere is 160 what is the volume

Mathematics
2 answers:
pantera1 [17]2 years ago
8 0

Answer:

2.14x10^{2}

Have a wonderful day!

IgorLugansk [536]2 years ago
6 0

Answer:

im going to have to go with V=2.14×10^{6}

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What is 1/5 × -3/2 +4/5 × -2/7 × -1/6 × -2/7
velikii [3]

Answer:

\frac{-457}{1470}

Step-by-step explanation:

\frac{1}{5} \times \frac{-3}{2} + \frac{4}{5} \times \frac{-2}{7} \times \frac{-1}{6} \times \frac{-2}{7}

(\frac{1}{5} \times \frac{-3}{2}) + (\frac{4}{5} \times \frac{-2}{7} \times \frac{-1}{6} \times \frac{-2}{7})

\frac{-3}{10} +\frac{-16}{1470}

=\frac{-457}{1470}

4 0
3 years ago
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Would you rather have 1 of 8 slices from a 10" pizza or 1 of 10 slices from a 14" pizza?
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1 8 of a pizza you get more
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2 years ago
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An Airliner has a capacity for 300 passengers. If the company overbook a flight with 320 passengers, What is the probability tha
TEA [102]

Answer:

The probability is   P(X  >300 ) = 0.97219

Step-by-step explanation:

From the question we are told that

 The capacity of  an Airliner  is  k =  300 passengers

 The sample size n =  320 passengers

  The probability the a randomly selected passenger shows up on to the airport

    p = 0.96

Generally the mean is mathematically represented as

    \mu  =  n*  p

  => \mu  =  320 *  0.96

    => \mu  = 307.2

Generally the standard deviation is  

    \sigma =  \sqrt{n *  p *  (1 -p ) }

=>  \sigma =  \sqrt{320  *  0.96 *  (1 -0.96 ) }

=> \sigma =3.50

Applying Normal approximation of binomial distribution

Generally the probability that there will not be enough seats to accommodate all passengers is mathematically represented as

  P(X  > k ) =  P( \frac{ X -\mu }{\sigma }  >  \frac{k - \mu}{\sigma } )

Here \frac{ X -\mu }{\sigma }  =Z (The \ standardized \  value \  of  \ X )

=>P(X  >300 ) =  P(Z >  \frac{300 - 307.2}{3.50} )

Now applying  continuity correction we have

    P(X  >300 ) =  P(Z >  \frac{[300+0.5] - 307.2}{3.50} )    

=>    P(X  >300 ) =  P(Z >  \frac{[300.5] - 307.2}{3.50} )

=>    P(X  >300 ) =  P(Z >  -1.914 )

From the z-table  

    P(Z >  -1.914 ) =  0.97219

So

    P(X  >300 ) = 0.97219

8 0
3 years ago
You want to find the width, AB, of a river. You walk along the edge of the river 100 ft and mark point C. Then
otez555 [7]

Answer:

I have been trying to figure this one out, I'm sorry but i don't know the answer

Step-by-step explanation:

i hate math

4 0
2 years ago
Select the two figures that are similar to the 5 by 10 figure that is shown.
Lapatulllka [165]

Answer:

Figure (i) and (iv)

Step-by-step explanation:

Given:

Optional figure is given in attached file.

We need to find two figures that are similar to the 5 by 10 figure.

All the given figure are m\times n form.

Where m represent the number of rows and n represent the number of columns.

Solution:

Observe that in the given figure 5 by 10, the number of rows is 5 and number of columns is 10, that is, the number of columns is double of that the number of rows.

So we need to find two such figures whose number of columns is double of the number of rows.

From the given figures, figure (i) the number of rows is 2 and number of columns is 4, which is double of number of rows. so it is similar to 5 by 10 figure.

Similarly in figure (iv), the number of rows is 4 and number of columns is 8. so the number of columns is double the number of rows, so it is similar to the figure 5 by 10.

Therefore, the two figures that are similar to 5 by 10 figure are given in attached file such as (i) and (iv).

6 0
2 years ago
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