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2 years ago

If the three angles of a quadrilateral are 120, 130, 10 then the fourth angle is

Mathematics

2 answers:

Bezzdna [24]2 years ago

7 0

100
Because the sum of all four angles of the quadrilateral is 360º, so u need 100 to get the 360

Aloiza [94]2 years ago

4 0

Answer:

100

Step-by-step explanation:

120 + 130 + 10 = 260

360 - 260 = 100

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What is the slope of (-6,8) and (-6,2)

SpyIntel [72]

Answer:

Undefined

Step-by-step explanation:

First, slope is change in y over change in x, or rise over run. Plugging these points in (y1-y2)/(x1-x2)=(2-8)/(-6--6), or -6/0. Oh no! You can't divide by 0. Therefore, the slope is undefined.

You can also see this by graphing the line, which is a straight vertical line. Vertical lines have undefined slopes.

4 0

2 years ago

Read 2 more answers

Find the angles between -pi and pi that satisfy:<br><br> (−√3) sin(v)+cos(v)=√3

MAXImum [283]

Observe that

$\sin\left(\dfrac\pi6-v\right)=\sin\dfrac\pi6\cos v-\cos\dfrac\pi6\sin v=\dfrac12\cos v-\dfrac{\sqrt3}2\sin v$

In the original equation, divide both sides by $\dfrac12$ :

$-\sqrt3\sin v+\cos v=\sqrt3\implies\dfrac12\cos v-\dfrac{\sqrt3}2\sin v=\dfrac{\sqrt3}2$

$\implies\sin\left(\dfrac\pi6-v\right)=\dfrac{\sqrt3}2$

Next,

$\sin x=\dfrac{\sqrt3}2\implies x=\dfrac\pi3+2n\pi,x=\dfrac{2\pi}3+2n\pi$

where $n$ is any integer. Then

$\sin\left(\dfrac\pi6-v\right)\implies v=-\dfrac\pi6-2n\pi,v=-\dfrac\pi2-2n\pi$

Fix $n=0$ to ensure $-\pi$ , so that

$v=-\dfrac\pi6,v=-\dfrac\pi2$

3 0

3 years ago

HELP ME PLEASE!!!! PLEASE EXPLAIN ASWELL ( FOR 30 POINTS)

mina [271]

Answer:

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Step-by-step explanation:

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3 years ago

What is the equation of this line in slope-intercept form (-1,5) and (1,-3)?

Harrizon [31]

Slope intercept means
y=mx+c
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the equation of the line is
y-5 = -4(x+1)
4x+y-1=0
changing the equation into slope intercept form
y= -4x+1

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3 years ago

Solve the quadratic equation by factoring-

shtirl [24]

Answer:

c- (2x+3)(x+1)

Step-by-step explanation:

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2 years ago

If the three angles of a quadrilateral are 120, 130, 10 then the fourth angle is​

If the three angles of a quadrilateral are 120, 130, 10 then the fourth angle is