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3 years ago

Pls help I’ll give you 38 points

Mathematics

2 answers:

polet [3.4K]3 years ago

5 0

Answer:

Step-by-step explanation:

I cant see it

murzikaleks [220]3 years ago

4 0

Answer:

The photo is hazzy-

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ANSWER FAST AND GET ALOT OF POINTS

Sergeu [11.5K]

Answer:

DUDE WHO GAVE YOU THESE QUESTIONS

6 0

3 years ago

Calculate the volume of a cube with side length of 7mm.

olga nikolaevna [1]

Answer:

${7}^{3} = 7 \times 7 \times 7 = 147 {m}^{3} \\ to \: calculate \: the \: volume \: of \: a \: cube \: we \: need \: to \: use \: this \: formula \\ {x}^{3} \\ x = side \: length$

4 0

3 years ago

Circle A was translated 3 units to the left and 4 units up to create Circle B. Which rule describes the translation that was app

kifflom [539]

Answer:

$B = (x - 3, y + 4)$

Step-by-step explanation:

Given

Represent the coordinates of circle A with (x,y)

<u>Translation</u>

Left = 3 units

Up = 4 units

Required

Determine the coordinates of B

When a point (x,y) is translated by h units left, the new point is: (x - h, y)

When a point (x,y) is translated by b units up, the new point is: (x, y + b)

So, when circle A is completely translated to B, the new points of B is:

$B = (x - h, y + b)$

In this case:

$h = 3\ and\ b = 4$

So:

$B = (x - 3, y + 4)$

4 0

4 years ago

Simplify 9/12 into simplest form

Kryger [21]

Both 9 and 12 can be divided by 3.
Divide both 9 and 12 by 3.
9/3=3 12/3=4
9/12=3/4
3/4 is the simplest form of 9/12

4 0

3 years ago

Read 2 more answers

A track star runs two races on a certain day. The probability thathe wins the first race is 0.7, the probability that he wins th

NARA [144]

Answer:

a) 80% probability that he wins at least one race.

b) 30% probability that he wins exactly one race.

c) 20% probability that he wins neither race.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that he wins the first race.

B is the probability that he wins the second race.

C is the probability that he does not win any of these races.

We have that:

$A = a + (A \cap B)$

In which a is the probability that he wins the first race but not the second and $A \cap B$ is the probability that he wins both these races.

By the same logic, we have that:

$B = b + (A \cap B)$

The probability that he wins both races is 0.5.

This means that $A \cap B = 0.5$

The probability that he wins the second race is 0.6

This means that $B = 0.6$

$B = b + (A \cap B)$

$0.6 = b + 0.5$

$b = 0.1$

The probability that he wins the first race is 0.7.

This means that $A = 0.6$

$A = a + (A \cap B)$

$0.7 = a + 0.5$

$a = 0.2$

A) he wins at least one race.

This is

$P = a + b + (A \cap B) = 0.2 + 0.1 + 0.5 = 0.8$

There is an 80% probability that he wins at least one race.

B) he wins exactly one race.

This is

$P = a + b = 0.2 + 0.1 = 0.3$

There is a 30% probability that he wins exactly one race.

C) he wins neither race

Either he wins at least one race, or he wins neither. The sum of these probabilities is 100%.

From a), we have that there is an 80% probability that he wins at least one race.

So there is a 100-80 = 20% probability that he wins neither race.

6 0

3 years ago