Answer:
1) 4, 7, 12 and 19
Tenth term = 103
2) 2, 8, 18, 32
Tenth term =200
Step-by-step explanation:
Given the nth term of the sequence
1) f(n)= n²+3
When n = 1
f(1) = 1²+3
f(1) = 4
When n = 2
f(2) = 2²+3
f(2) =4+3
f(2) = 7
When n = 3
f(3) = 3²+3
f(3) = 9+3
f(3)=12
When n =4
f(4) = 4²+3
f(4) = 16+3
f(4) = 19
The first four terms are 4, 7, 12 and 19
f(10)= 10²+3
f(10) = 103
Tenth term is 103
2) f(n) = 2n²
When n = 1
f(1) = 2(1)²
f(1) = 2
When n = 2
f(2) = 2(2)²
f(2) = 2(4)
f(2) = 8
When n= 3
f(3)= 2(3)²
f(3) = 2(9)
f(3) = 18
When n= 4
f(4) = 2(4)²
f(4) = 2(16)
f(4) =32
The first four terms are 2, 8, 18, 32
f(10) = 2(10)²
f(10) =2(100)
f(20) = 200
The tenth term is 200
Answer:
Step-by-step explanation:
3 Great Ways to Teach Adding Integers
Typically, you should begin by having your students think about real world examples of positive and negative integer. ...
Then, model this example using counter chips.
Finally, have your students model addition problems using the counter chips.
Answer:
<u>2772 in³</u>
Step-by-step explanation:
- Volume = πr²h
- V = 22/7 x 7 x 7 x 18
- V = 22 x 7 x 18
- V = 154 x 18
- V = <u>2772 in³</u>
