Answer:
If we have a function f(x) that has an inverse g(x), we have the relations:
f( g(x)) = x
g( f(x)) = x
Then if the coordinates for the function f(x) are points like (x₁, y₁)
The coordinates for the inverse, g(x), will be (y₁, x₁)
Now let's look at the table, here we can see that the coordinates for f(x) are:
(0, 650)
(100, 550)
(200, 450)
(340, 310)
(650, 0)
Then the coordinates of the inverse function will be:
(650, 0)
(550, 100)
(450, 200)
(340, 310)
(0, 650)
Answer:
15 days
Step-by-step explanation:
3x5=15 days
I know its a long problem but i have to shiw how i got my answer.
Answer:
1/sqrt10
Step-by-step explanation:
1) Find out cosA using formula (cosA)^2+(sinA)^2=1
The module of cosA= sqrt (1- (-3/5)^2)= sqrt 16/25=4/5
So cosA=-4/5 or cosA=4/5.
Due to the condition 270degrees< A<360 degrees, 0<cosA<1 that's why cosA=4/5.
2) Find sinA/2 using a formula cosA= 1-2sinA/2*sinA/2 where cosA=4/5.
(sinA/2)^2= 0.1
sinA= sqrt 0.1= 1/ sqrt10 or sinA= - sqrt 0.1= -1/sqrt10
But 270°< A< 360°, then 270/2°<A/2<360/2°
135°<A/2<180°, so sinA/2 must be positive and the only correct answer is
sin A/2= 1/sqrt10
