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NemiM [27]
3 years ago
9

When solid Ni metal is put into an aqueous solution of Sn(NO3)2, solid Sn metal and a solution of Ni(NO3)2 result. Write the net

ionic equation for the reaction.
Chemistry
1 answer:
Monica [59]3 years ago
4 0

Answer:

Ni + Sn^2+ —> Sn + Ni^2+

Explanation:

First let us generate an elemental equation for the reaction. This is illustrated below:

Ni + Sn(NO3)2 —> Sn + Ni(NO3)2

From the equation above, a solid metal Sn is formed.

Now we can generate a net ionic equation as follows:

Ni + Sn^2+ —> Sn + Ni^2+

You might be interested in
A binary ionic compound is known to contain a cation with 51 protons and 48 electrons. The anion contains one-third the number o
7nadin3 [17]

Answer:

SbCl_3

Explanation:

The cation contains 51 protons and 48 electrons. The electrons are only lost not protons, so the element which corresponds to atomic number 51 is the cation which is Antimony (Sb).

Also, the charge on the cation is 51 - 48 = 3

This is because neutral atom contains the same number of electrons as protons.

Given the anion has one-third protons as cation which means thta:

Number of protons in anion = \frac {51}{3}=17

This corresponds to chlorine atom. The electrons are 1 greater than protons means that it has gain 1 electron.

So,

Sb     Cl

3         1

Cross multiply the valency.

So, formula is SbCl_3

4 0
3 years ago
A waterbed mattress has the following dimensions: 210 cm X 160 cm X 25 cm. The density of water is 62.4lb/ft3. What is the weigh
artcher [175]

<u>Answer:</u> The weight of water bed in pounds is 1850.16 lb

<u>Explanation:</u>

To calculate the volume of cuboid, we use the equation:

V=lbh

where,

V = volume of cuboid

l = length of cuboid = 210 cm

b = breadth of cuboid = 160 cm

h = height of cuboid = 25 cm

Putting values in above equation, we get:

V=210\times 160\times 25=8.4\times 10^5cm^3=29.65ft^3      (Conversion factor:  1cm^3=3.53\times 10^{-5}ft^3 )

To calculate the mass of waterbed, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of waterbed = 62.4lb/ft^3

Volume of waterbed = 29.65ft^3

Putting values in above equation, we get:

62.4lb/ft^3=\frac{\text{Mass of waterbed}}{29.65ft^3}\\\\\text{Mass of waterbed}=(62.4lb/ft^3\times 29.65ft^3)=1850.16lb

Hence, the weight of water bed in pounds is 1850.16 lb

7 0
4 years ago
Convert the following sentence into an equation and balance it.
Ivan
Djsktdotsktdktđktkskrdkt
5 0
3 years ago
Need help !!!!! Stuck
Leya [2.2K]
<h2>Hello!</h2>

The answer is:

The new pressure will be equal to 6 atm.

P_{2}=6atm

<h2>Why?</h2>

Since we know that the temperature is constant, we can use the Boyle's Law to solve the problem.

The Boyle's Law establishes that when the temperature is kept constant, the pressure and the volume will be proportional.

So, we have the equation:

P_{1}V_{1}=P_{2}V_{2}

We are given,

P_{1}=2atm\\V_{1}=150mL\\V_{2}=50mL

Substituting and isolating P_{2} from the Boyle's Law, we have:

P_{1}V_{1}=P_{2}V_{2}\\\\P_{2}=\frac{P_{1}V_{1}}{V_{2}}\\\\P_{2}=\frac{2atm*150mL}{50mL}=6atm

Hence, the new pressure will be equal to 6 atm.

P_{2}=6atm

Have a nice day!

8 0
3 years ago
In the explosion of a hydrogen-filled balloon, 0.80 g of hydrogen reacted with 6.4 g of oxygen. How many grams of water vapor ar
mylen [45]

 0.4 moles H2O x (18.0 g / mole) = 7.2 g H2O

Explanation:

write the values given in the question

In an explosion of hydrogen balloon, 0.80g of hydrogen is reacted with 6.4g of oxygen.

Write the balanced equation

2 H2 + O2 ---> 2 H2O

0.80 g H2 x (1 mole / 2g) = 0.4 moles H2

6.4 g O2 x (1 mole / 32g) = 0.2 moles O2

from balanced equation, 2 moles H2 react with 1 mole O2

therefore

0.4 moles H2 x (1 mole O2 / 2 moles H2) = 0.2 moles O2

since we need 0.2 moles O2 to react with all the H2 and we have exactly that amount, the amounts are said to be

"stoichiometric" and either reactant can be considered limiting

from the balanced equation, 2 moles H2 --> 2 moles H2O.. therefore

0.4 moles H2 x (2 moles H2O / 2 moles H2) = 0.4 moles H2O

Then

0.4 moles H2O x (18.0 g / mole) = 7.2 g H2O

8 0
3 years ago
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