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kow [346]
3 years ago
13

Solve the following equation by combining like terms: 4y - 2y = 18

Mathematics
2 answers:
Lelechka [254]3 years ago
8 0

Answer:

y = 9

Step-by-step explanation:

Collect the like terms:

2y = 18

Divide both sides by 2 to make y on its own

y = 9

olga nikolaevna [1]3 years ago
3 0
4y-2y=18
(Collect like terms)
2y=18
(Divide like terms)
y=9
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janice has twice as many stickers as melvin. ryan has 5 more stickers than janice. if melvin has h stickers, how many stickers d
JulsSmile [24]

Answer:

Ryan has 2H + 5 stickers.

Step-by-step explanation:

Let J = Janice

Let M = Melvin

Let R = Ryan

J = 2*M

R = J + 5

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J = 2*H

R = 2H + 5

3 0
3 years ago
The revenue generated by the band is given by the expression 50x+150
Mariana [72]

Answer:

(1, 10) and (40, 0)

Step-by-step explanation:

Given expression 50x+150

inequality is

50x + 150y > 1500

it means that if we plug value of x and y from given option in  50x+150 then it should be greater than 1500.

lets check for all the option

(1,10)

50*1 + 150*10 = 50+1500 = 1550

Since , 1550 is greater than 1500, (1,10) is the solution for the inequality given

(10, 1)

50*10 + 150*1 = 500+ 150 = 650

Since , 650 is less than 1500, (10,1) is not the solution for the inequality given

(0, 10)

50*0 + 150*10 = 0 + 1500 = 1500

Since , 1500 is equal to 1500 but not greater than 1500, (0,10) is not the solution for the inequality given

(40, 0)

50*40 + 150*0 = 2000 + 0 = 2000

Since , 200 is greater than 1500, (40,0) is the solution for the inequality given above.

Thus, from the given option there are two solution for 50x + 150y > 1500

(1, 10) and (40, 0)

6 0
3 years ago
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Barbara ordered a set of beads. Of the beads she received, 12 were red and 28 were a different color. What percentage of the bea
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Answer393

Theory cause I need points
7 0
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<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%7B%7D%5E%7B2%7D%20-%204%20%7D%7B%20%5Csqrt%7Bx%20%7B%7D%5E%7B2%7D%20-%206x%2
Nimfa-mama [501]

First of all, we can observe that

x^2-6x+9 = (x-3)^2

So the expression becomes

\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}

This means that the expression is defined for every x\neq 3

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2

Since we can't accept 3 as an answer, the actual solution set is

(-\infty,-2] \cup [2,3) \cup (3,\infty)

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3 years ago
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I really think it is 180

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