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kow [346]
3 years ago
13

Solve the following equation by combining like terms: 4y - 2y = 18

Mathematics
2 answers:
Lelechka [254]3 years ago
8 0

Answer:

y = 9

Step-by-step explanation:

Collect the like terms:

2y = 18

Divide both sides by 2 to make y on its own

y = 9

olga nikolaevna [1]3 years ago
3 0
4y-2y=18
(Collect like terms)
2y=18
(Divide like terms)
y=9
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What is the solution to the system of equations graphed below? ​
padilas [110]

Step-by-step explanation:

The solution can be found by identifying the point of intersection of the 2 graphed lines.

As we can see, they intersect each other at the point (2, -3). This is our solution for the equations.

4 0
3 years ago
Show that a = −1 + √3i and b = 2 satisfy 1/a+b=1/a + 1/b
Zarrin [17]

Answer:

LHS = \frac{1 - \sqrt3i}{4} = RHS = \frac{1 - \sqrt3i}{4}

Step-by-step explanation:

Data provided in the question:

a = −1 + √3i and b = 2

to prove:

\frac{1}{a+b}=\frac{1}{a} + \frac{1}{b}

Considering the LHS

⇒ \frac{1}{a+b}

substituting the value of a and b, we get

⇒ \frac{1}{−1 + \sqrt3i+2}

or

⇒ \frac{1}{1 + \sqrt3i}

on multiplying and dividing by conjugate ( 1 - √3i )

we get

\frac{1}{1 + \sqrt3i}\times\frac{1 - \sqrt3i}{1 - \sqrt3i}

or

\frac{1 - \sqrt3i}{(1^2 - (\sqrt3i)^2}

or

\frac{1 - \sqrt3i}{1 + 3}              (as (√i)² = -1 )

or

\frac{1 - \sqrt3i}{4}

Now,

considering the RHS

\frac{1}{a} + \frac{1}{b}

substituting the value of a and b, we get

⇒ \frac{1}{-1 + \sqrt3i} + \frac{1}{2}

or

⇒ \frac{2\times1 + ( -1 + \sqrt3i)\times1}{(-1 + \sqrt3i)\times2}

or

⇒ \frac{2 + ( -1 + \sqrt3i)}{(-1 + \sqrt3i)\times2}

or

⇒ \frac{1 + \sqrt3i}{(-1 + \sqrt3i)\times2}

now,

on multiplying and dividing by conjugate ( -1 - √3i )

we get

\frac{1 + \sqrt3i}{(−1 + \sqrt3i)\times2}\times\frac{-1 - \sqrt3i}{-1 - \sqrt3i}

or

\frac{1 + \sqrt3i}{(−1 + \sqrt3i)\times2}\times\frac{-1( 1 + \sqrt3i)}{-1 - \sqrt3i}

or

\frac{(1 + \sqrt3i}^2\times(-1){((-1)^2 - (\sqrt3i)^2)\times2}

or

\frac{(1^2 + (\sqrt3i)^2+2(1)(\sqrt3i)\times(-1)}{(1 + 3)\times2}

or

\frac{(1 - 3 + 2\sqrt3i)\times(-1)}{(4)\times2}

or

\frac{(-2 + 2\sqrt3i)\times(-1)}{(4)\times2}

or

\frac{-2( 1 - 2\sqrt3i)\times(-1)}{(4)\times2}

or

\frac{( 1 - 2\sqrt3i)}{(4)}

Since, LHS = RHS

hence satisfied

3 0
3 years ago
A mechanic buys $14.56 worth of parts from a supplier. If he pays for the parts with a $20 bill, how much change will he receive
balu736 [363]

This is a basic subtraction problem :-).

You will subtract how much money the mechanic gives to the supplier; which in this case will be $20, by the total amount of the parts which is $14.56.

20-14.56 = 5.44

Therefore, he will receive $5.44 in change for the transaction.

7 0
4 years ago
Read 2 more answers
Please help me with this
weeeeeb [17]
The answer is B. -3 because that's x and you add them together and get greater than.
5 0
3 years ago
Which expression is equivalent to 16(30x – 24y) –18 (32x – 16y)?
HACTEHA [7]

Answer:

\frac{1}{6}\left(30x-24y\right)-\frac{1}{8}\left(32x-16y\right)

Step-by-step explanation:

there ya go

3 0
3 years ago
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