The formula
in solving the integral of the infinity of 3 is ∫3<span>∞?</span>(1<span>)÷((</span>x−2<span><span>)<span><span>(3/</span><span>2)</span></span></span>)</span><span>dx</span>
Substitute the numbers given
then solve
limn→inf∫3n(1/((n−2)(3/2))dn
limn→inf[−2/(n−2−−−−−√)−(−2/3−2−−−−√)
=0+2=2
Solve for the integral of 2 when 2 is approximate to 0.
Transpose 2 from the other side to make it -2
∫∞3(x−2)−3/2dx=(x−2)−1/2−1/2+C
(x−2)−1/2=1x−2−−−−√
0−(3−2)−1/2−1/2=2
<span> </span>
5x+2y=3
-5x on both sides
2y=3-5x
divide by 2 on both sides
y=3/2-5/2x
rewrite in order (optional depending on teacher)
y=-5/2x+3/2
Answer:
Step-by-step explanation:
Any parallelogram has the area of the length between the left and right side times the length from the top to the bottom.
Here the horizontal length is easy, it's just 6. it tries to trick you witht he vertical length. You want the straight up nd down line from the top and bottom, which is that 8 on the right. so the area is 6*8
6*8 = 48
Let f(x) =y be another equation
where the slope of f(x) =y cannot be 4/5, can it be other quation
