x + 3, x > -3 is the piece which will be included in the given function f(x) = [ x + 3 ]. This can be obtained by removing modulus and finding the value for x.
<h3>Which piece will the function include?</h3>
Given that,
f(x) = [ x + 3 ] which is an absolute value function.
Therefore,
| x+3 | > 0
By removing the modulus,
x+3 > 0
x > - 3
Hence x + 3, x > -3 is the piece which will be included in the given function f(x) = [ x + 3 ].
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Question: Consider this absolute value function.
f(x) = [ x + 3 ]
If function f is written as a piecewise function, which piece will it include?
A. x + 3, x > 3
B. x + 3, x > -3
C. -x + 3, x < -3
D. -x - 3, x < 3
Answer:
6 units
Step-by-step explanation:
I will just assume that you made a typo when typing the question when saying AB is 6√3. Here is the solution if AB = 6√2.
Since it is given that ABC is a right triangle and x labels each of the legs, the triangle is a right isoceles triangle.
Now we can use the right isoceles triangle theorem to solve the problem. This theorem states that if a leg is "x" in a right isoceles triangle, then the hypotenuse is equal to x√2.
Here, the hypotenuse is equal to 6√2. To figure out the legs, you need to solve the equation 6√2 = x√2. It is solved here:
6√2 = x√2 (Divide by √2)
x = 6
The length of the legs are 6 units.
Answer: 7,8,9
Step-by-step explanation:
Let the numbers be a, a+1 and a+2. Therefore, based on the question, this will be:
= (a + 1)(a + 2) = 72
a² + 2a + a + 2 = 72
a² + 3a + 2 - 72 = a
a² + 3a - 70 = 0
a² + 10a - 7a - 70 = 0
a(a + 10) - 7(a + 10)
a - 7 = 0
a = 7
Since a = 7
a + 1 = 7+1 = 8
a + 2 = 7+2 = 9
The numbers are 7,8 and 9
Answer:
y=-3/2x+5
Step-by-step explanation:
you look for your y-intercept first then you find 2 points and do rise over run to get y=-3/2x+5
