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erastovalidia [21]
3 years ago
15

James has $32 and earns $10 per week for his allowance. What is the initial value for the scenario described?

Mathematics
2 answers:
Verdich [7]3 years ago
5 0

This answer is confirmed!

stealth61 [152]3 years ago
3 0
Your answer should be B.
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Can some one can do both​
patriot [66]
A) m=-3
B) n=-17
hope this helps x
would love to have brainliest if it is right :)
8 0
3 years ago
The height in meters of a toy rocket at t seconds can be found by the
OlgaM077 [116]

Answer:   81.2

Step-by-step explanation:

h(t) = -5t² + 40t + 1.2

h(4) = -5(4)² + 40(4) + 1.2                   We plug 4 seconds as t, and solve h(4)

h(4) = -80 + 160 + 1.2

h(4) = 80 + 1.2

h(4) = 81.2

4 0
3 years ago
Find the inverse of the given​ matrix, if it exists.Aequals=left bracket Start 3 By 3 Matrix 1st Row 1st Column 1 2nd Column 0 3
BabaBlast [244]

Answer:

A^{-1}=\left[ \begin{array}{ccc} \frac{1}{9} & \frac{4}{27} & - \frac{2}{27} \\\\ \frac{8}{9} & \frac{5}{27} & \frac{11}{27} \\\\ - \frac{4}{9} & \frac{2}{27} & - \frac{1}{27} \end{array} \right]

Step-by-step explanation:

We want to find the inverse of A=\left[ \begin{array}{ccc} 1 & 0 & -2 \\\\ 4 & 1 & 3 \\\\ -4 & 2 & 3 \end{array} \right]

To find the inverse matrix, augment it with the identity matrix and perform row operations trying to make the identity matrix to the left. Then to the right will be inverse matrix.

So, augment the matrix with identity matrix:

\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 4&1&3&0&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]

  • Subtract row 1 multiplied by 4 from row 2

\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]

  • Add row 1 multiplied by 4 to row 3

\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&2&-5&4&0&1\end{array}\right]

  • Subtract row 2 multiplied by 2 from row 3

\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&-27&12&-2&1\end{array}\right]

  • Divide row 3 by −27

\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]

  • Add row 3 multiplied by 2 to row 1

\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]

  • Subtract row 3 multiplied by 11 from row 2

\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&0&\frac{8}{9}&\frac{5}{27}&\frac{11}{27} \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]

As can be seen, we have obtained the identity matrix to the left. So, we are done.

6 0
3 years ago
A group of 52 people attend a ball game. There were three times as many men as women in the group. Write and solve a system of e
kkurt [141]

Answer:

lets call the children, c, and call adult, a,

c+a= 52       eq 1: a=52-c

c=3a            eq 2

take a's value from eq 1 and plug it into eq 2

c=3(52-c)

c=156-3c

4c=156

c=39 the number of children that attended the ball game.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Some one help please algebra ..<br>-6=3x-6y<br>4x=4+5x
yanalaym [24]
X=2y-2

x=-4 

hope i helped

5 0
3 years ago
Read 2 more answers
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