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barxatty [35]
3 years ago
7

TEACHER QUESTION

Mathematics
2 answers:
DedPeter [7]3 years ago
5 0

Answer: 62.33 57.67

Step-by-step explanation:

Schach [20]3 years ago
3 0

Answer:

Step-by-step explanation:

Year 2004: 62.33

Year 2013: 57.67

2013-2004 = 9

57.67-62.33 =-4.66

-4.66/9 = -0.517777778 which is the average rate of change

Here the the avg. rate of change means that on average, the change in rainfall every year is -0.517777... inches

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Complete the the ratio to convert the units of measure from ounces to grams to ounces ?​
otez555 [7]

Answer:

84 and 5

3x28=84

140 divided by 28=5

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The density curve below represents the number of hours that Mrs. Schultz's students spent studying for
Brut [27]

Answer:

the mean of the study times is greater than the median

Step-by-step explanation:

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3 years ago
What is the y-intercept of the line represented by y = 4x?​
Brut [27]

Answer: 0

Step-by-step explanation: In order to identify the <em>y-intercept</em> of this equation, we want to get this equation into slope-intercept form which is more commonly known as y = mx + b form.

The problem is our equation doesn't match up quite so well with the formula y = mx + b. Our slope or <em>m</em> which is represented by the coefficient of the <em>x</em> <em>term</em> is clearly +4 but what is our y-intercept or b?

Well y = 4x can be thought of as y = 4x + 0 so you can see that our b or y-intercept equals 0.

5 0
3 years ago
There are 4 boys and 9 girls on the track team how many students are on the track team altogether
zhannawk [14.2K]

Answer:

13 students

Step-by-step explanation:

4 plus 9 = 13

4 0
3 years ago
Read 2 more answers
(a) A lamp has two bulbs, each of a type with average lifetime 1400 hours. Assuming that we can model the probability of failure
Temka [501]

Answer:

For first lamp ; The resultant probability is 0.703

For both lamps; The resultant probability is 0.3614

Step-by-step explanation:

Let X be the lifetime hours of two bulbs

X∼exp(1/1400)

f(x)=1/1400e−1/1400x

P(X<x)=1−e−1/1400x

X∼exp⁡(1/1400)

f(x)=1/1400 e−1/1400x

P(X<x)=1−e−1/1400x

The probability that both of the lamp bulbs fail within 1700 hours is calculated below,

P(X≤1700)=1−e−1/1400×1700

=1−e−1.21=0.703

The resultant probability is 0.703

Let Y be a lifetime of another lamp two bulbs

Then the Z = X + Y will follow gamma distribution that is,

X+Y=Z∼gamma(2,1/1400)

2λZ∼

X+Y=Z∼gamma(2,1/1400)

2λZ∼χ2α2

The probability that both of the lamp bulbs fail within a total of 1700 hours is calculated below,

P(Z≤1700)=P(1/700Z≤1.67)=

P(χ24≤1.67)=0.3614

The resultant probability is 0.3614

8 0
2 years ago
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