Answer:
For 5 packets of flavoring, ounce of water = 60.
For 84 ounces of water, number of packets of flavoring = 7.
For 10 packets of flavoring, ounce of water = 120.
For 144 ounces of water, number of packets of flavoring = 12.
Step-by-step explanation:
From the table, it is clear that the ratio between the packets of flavoring to ounce of water is 2:24 = 1:12.
So, for 5 packets of flavoring, ounce of water = 5 × 12 = 60.
For 84 ounces of water, number of packets of flavoring = 7 × 1 = 7.
For 10 packets of flavoring, ounce of water = 10 × 12 = 120.
For 144 ounces of water, number of packets of flavoring = 12 × 1 = 12.
Please refer to the attached table.
Answer:
(-1, 4)
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define systems</u>
10x + 6y = 14
-x - 6y = -23
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Elimination</em>
- Add 2 equations together: 9x = -9
- Divide 9 on both sides: x = -1
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: -x - 6y = -23
- Substitute in <em>x</em>: -(-1) - 6y = -23
- Multiply: 1 - 6y = -23
- Subtract 1 on both sides: -6y = -24
- Divide -6 on both sides: y = 4
4048 is the correct answer
Answer:
166,833
Step-by-step explanation:
t
n
=
a
+
(
n
−
1
)
d
999
=
3
+
(
n
−
1
)
3
999
=
3
+
3
n
−
3
999
=
3
n
n
=
333
We can now use the formula
s
n
=
n
2
(
2
a
+
(
n
−
1
)
d
)
)
to determine the sum.
s
333
=
333
2
(
2
(
3
)
+
(
333
−
1
)
3
)
s
333
=
333
2
(
1002
)
s
333
=
166
,
833
Hopefully this helps!
Answer: (A) 24
Step-by-step explanation:
