Answer:
Part a) The inequality that represent the situation is
Part b) The possible lengths of the shortest piece of wire are all positive real numbers less than or equal to
Step-by-step explanation:
Let
x------> the length of the first wire
3x---> the length of the second wire
2(3x)=6x -----> the length of the third wire
Part a) WRITE AN *INEQUALITY* THAT MODELS THE SITUATION
we know that
The inequality that represent the situation is
Part b) WHAT ARE THE POSSIBLE LENGTHS OF THE SHORTEST PIECE OF WIRE?
we know that
The shortest piece of wire is the first wire
so
Solve the inequality
Divide by 10 both sides
The possible lengths of the shortest piece of wire are all positive real numbers less than or equal to
The correct answers are #1 and #4
The slope-intercept form:
m - slope
b - y-intercept
We have .
Transform to the slope-intercept form.
<em>subtract 3x from both sides</em>
<em>divide both sides by 6</em>
Answer:
Answer:
The answer to your question is Yes, she has enough paint.
Step-by-step explanation:
Data
base = 12 ft
height = 8 ft
window = 3 ft x 3 ft
Process
1.- Calculate the area of the wall
Area = base x height
Area = 12 x 8
Area = 96 ft²
2.- Calculate the are of the wall
Area = side x side
Area = 3 x 3
Area = 9 ft²
3.- Calculate the area that need to be painted
Area painted = Area of the wall - Area of the window
-Substitution
Area painted = 96 - 9
= 87 ft²
4.- Conclusion
She has enough paint to paint the wall (90 ft² > 87 ft²).
C is your hypotenuse and a/b are the legs
A = 5
B = 12
OR
A = 12
B = 5
Either work. I'll stick with the first one.
c^2 = 12^2 + 5^2
c^2 = 144 + 25
c^2 = 169
c = sqrt 169
c = 13
Ans: 13 inches (dont forget your units!)