To calculate amount accrued after a given period of time we use the compound interest formula: A= P(1+r/100)∧n where A i the amount, P is the principal amount, r is the rate of interest and n is the interest period.
In the first part; A= $ 675.54, r= 1.25% (compounded semi-annually) and n =22 ( 11 years ), hence, 675.54 = P( 1.0125)∧22
= 675.54= 1.314P
P= $ 514.109 , therefore the principal amount was $ 514 (to nearest dollar)
Part 2
principal amount (p)= $ 541, rate (r) = 1.2 % (compounded twice a year thus rate for one half will be 2.4/2) and the interest period (n)= 34 (17 years×2)
Amount= 541 (1.012)∧34
= 541 ×1.5
= $ 811.5
Therefore, the account balance after $ 811.5.
Answer:
3q+21
Step-by-step explanation:
Answer:
-33 or 33
Step-by-step explanation:
The seventh term of an AP is written as:
The eleventh term of an AP is written as:
If the 7th term is 11 times the 11th term, then;
Expand to get:
We must have a=-52 and d=5
Or
a=52 and d=-5
For the first case, the 18th term is :
For the second case,
Answer:
It would be C since a scale factor of 2 makes the original A coordinate of (3,3) times 2 therefore the new coordinates being (6,6)
Step-by-step explanation:
