Im guessing by my predicition that it will be 0.11 that will continue
Answer:
x = -15 or 15
Step-by-step explanation:
We can simplify |x| - 3 = 15 to |x| = 15 because we can add 3 on both sides due to -3 being outside of the absolute value bars. Next, we can say that x is either 15 or -15 because of the absolute value (|15| is equal to 15 and |-15| is also equal to 15).
Answer:
The answer is 1.75 miles.
Step-by-step explanation:
Answer:
The first answer is correct.
Step-by-step explanation:
Line 5 says that the reason is due to substitution
Line 3 says m∠ SQT equals 180°
If we substitute 180° into the spot for m∠ SQT in line 4, we get solution option 1
Answer:
b. about 63.9 units and 41.0 units
Step-by-step explanation:
In question ∠a= 29° and Side of a= 15 and b= 20
Using sine rule of congruence of triangle.
⇒ ![\frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{sin C}](https://tex.z-dn.net/?f=%5Cfrac%7Ba%7D%7Bsin%20A%7D%20%3D%20%5Cfrac%7Bb%7D%7Bsin%20B%7D%20%3D%20%5Cfrac%7Bc%7D%7Bsin%20C%7D)
⇒ ![\frac{15}{Sin 29} = \frac{20}{sin B}](https://tex.z-dn.net/?f=%5Cfrac%7B15%7D%7BSin%2029%7D%20%3D%20%5Cfrac%7B20%7D%7Bsin%20B%7D)
Using value of sin 29°
⇒ ![\frac{15}{0.49} = \frac{20}{sin B}](https://tex.z-dn.net/?f=%5Cfrac%7B15%7D%7B0.49%7D%20%3D%20%5Cfrac%7B20%7D%7Bsin%20B%7D)
Cross multiplying both side.
⇒ Sin B= ![\frac{20\times 0.49}{15} = 0.65](https://tex.z-dn.net/?f=%5Cfrac%7B20%5Ctimes%200.49%7D%7B15%7D%20%3D%200.65)
∴ B= 41°
Now, we have the degree for ∠B= 41°.
Next, lets find the ∠C
∵ we know the sum total of angle of triangle is 180°
∴∠A+∠B+∠C= 180°
⇒ ![29+41+B= 180](https://tex.z-dn.net/?f=29%2B41%2BB%3D%20180)
subtracting both side by 70°
∴∠C= 110°
Now, again using the sine rule to find the side of c.
![\frac{b}{SinB} = \frac{c}{SinC}](https://tex.z-dn.net/?f=%5Cfrac%7Bb%7D%7BSinB%7D%20%3D%20%5Cfrac%7Bc%7D%7BSinC%7D)
⇒![\frac{20}{sin41} = \frac{C}{sin110}](https://tex.z-dn.net/?f=%5Cfrac%7B20%7D%7Bsin41%7D%20%3D%20%5Cfrac%7BC%7D%7Bsin110%7D)
Using the value of sine and cross multiplying both side.
⇒ C= ![\frac{20\times 0.94}{0.65} = 28.92](https://tex.z-dn.net/?f=%5Cfrac%7B20%5Ctimes%200.94%7D%7B0.65%7D%20%3D%2028.92)
∴ Side C= 28.92.
Now, finding perimeter of angle of triangle
Perimeter of triangle= a+b+c
Perimeter of triangle= ![(15+20+28.92)= 63.9](https://tex.z-dn.net/?f=%2815%2B20%2B28.92%29%3D%2063.9)
∴ Perimeter of triangle= 63.9 units