Volume of a quadrangular pyramid=(1/3)bh
b=base
h=height
b=area of the base=area of a square=8.4 ft * 8.4 ft=70.56 ft²
Pythagoras theorem:
hypotenuse²=leg₁² + leg₂²
data:
hypotenuse=9.6 ft
leg₁=height=h
leg₂=8.4 ft /2=4.2 ft
(9.6 ft)²= h² + (4.2 ft)²
92.16 ft²=h²+17.64 ft²
h²=92.16 ft²-17.64 ft²
h²=74.52 ft²
h=√(74.52 ft²)=8.63 ft.
Volume of this quadrangular pyramid=(1/3)(70.56 ft²)(8.63 ft)=202.9 ft³≈202.3 ft³
Answer: ≈202.3 ft³
Answer:d
Step-by-step explanation:
Well you can try rewriting it to this
answer is d 270
first start of by factoring and subtracting the 1 into the right side
sin(x) ( 2 sin (x) + 1) = -1
set each one equal to -1
sin( x) = -1 and 2 sin (x) +1 = -1
2 sin (x) = -2
sin ( x) = -1
so therefore we have our final equation
sin ( x ) = - 1 and sin (x) = -1
so then you look in your unit circle and find what coordinate equals -1 in terms of sin x
Answer:
3.73 ( The three is infinite)
Step-by-step explanation:
