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2 years ago

Is (9,5) a solution to the inequality y<5x+9?

Mathematics

2 answers:

Shalnov [3]2 years ago

5 0

Answer:

yes, it is

Step-by-step explanation:

andreyandreev [35.5K]2 years ago

4 0

Answer:

yes it is because 9 times 5 is 45 plus 9 is 54 and 54 is greater than 5

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I think it is either A or D

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The ordered pairs model an exponential growth function. (−1,21.875), (0,35), (1,56), (2,89.6) What is the function equation? f(x

Karolina [17]

Answer:

Given the ordered pairs, the exponential growth function would be represented by f(x)=35(1.6)^x.

Step-by-step explanation:

Exponential growth functions are represented by the following equation: f(x)=ab^x, where 'a'=initial value; 'b'=rate of growth; 'x'=independent value or time. Given the points, we see that the values of 'x' increase by 1 each time and dividing two 'y' values (35/21.875; 56/35; 89.6/56) gives us a change of 1.6. Rate is the change in y/the change in x, or 1.5/1, which is the value of 'b'. When 'x' is equal to 0, the value of 'y' is 35, so this represents the initial value, or 'a'. Plugging in these values will give us the final equation f(x)=35(1.6)^x.

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2 years ago

What is the slope intercpet form of a line that goes through (-1,2) and (0,3)

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3 years ago

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Ludmilka [50]

The inequality of this question would be 4

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2 years ago

For a given IQ test, an individual is considered a genius if their score falls more than three standard deviations from the mean

ki77a [65]

Answer:

$P(Z>3) = 1-P(Z$

So then the probability that an individual present and IQ higher than 3 deviation from the mean is 0.00135

And if we find the number of individuals that can be considered as genius we got: 0.00135*1500=2.025

And we can say that the answer is a.2

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

2) Solution to the problem

Let X the random variable that represent the IQ scores of a population, and for this case we know the distribution for X is given by:

$X \sim N(\mu=?,\sigma=?)$

We are interested on this probability

$P(X>X+3\mu)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

And we can find the following probablity:

$P(Z>3) = 1-P(Z$

So then the probability that an individual present and IQ higher than 3 deviation from the mean is 0.00135

And if we find the number of individuals that can be considered as genius we got: 0.00135*1500=2.025

And we can say that the answer is a/2.0

3 0

2 years ago