We can find m∠BCD like follows: m∠BCD=90°-45°=45<span>°
Now, m</span><span>∠DBC= 180°-(90°+45°)=45°
Remember that </span>

, so

We know that hypotenuse= BC= 3in and

=∠DBC)=45°, so replacing the values we get:

We can conclude that the segment CD is 2.12 in
The correct quadratic equation;
x2+7x-2=0
Working
Assuming the frame has a uniform thickness;
Then length of mirror and frame is 3+x and width 2+x
The area of mirror and frame area;
A=L*W
8=(3+x)(2+x)
8=(6+5x+x2)
Taking 8 to the Right hand side, we have:
x2+5x-2 =0
X-246-c4779952vhjjj23467890865
Answer:73. 0
Step-by-step explanation:
Radius=8.02
Tita =130
Area of sector = tita/360 x πr^2
130/360 x 22/7 x (8.02) ^2
130/360 x 22/7 x64. 3204
= 72.99
To the nearest tenth = 73.0
Divide commission amount by percentage:
83.50 / 0.40 = 208.75
Sales must be $208.75