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Stolb23 [73]
3 years ago
8

A water tank holds 666 gallons but is leaking at a rate of 4 gallons per week. A second water tank holds 888 gallons but is leak

ing at a rate of 7 gallons per week. After how many weeks will the amount of water in the two tanks be the same?
Mathematics
1 answer:
Katen [24]3 years ago
8 0

Answer:

74 weeks

Step-by-step explanation:

Given :

Let x = number of weeks

Gallon A:

Capacity = 666

Leak rate = 4 gallons per week

666 - 4x

Gallon B:

Capacity = 888

Leak rate = 7 gallons per week

888 - 7x

666- 4x = 888 - 7x

666 - 888 = - 7x + 4x

-222 = - 3x

x = 222 / 3

x = 74

After 74 weeks

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A pump empties the pool at the rate of 1000 gals every 4 hours how long does it take to pump our 20,000 gallons
8 0
3 years ago
What is the inverse of the function H(x)=3/4x+12
Mrac [35]

Answer:

h^{-1}(x) = \frac{4x-48}{3}

Step-by-step explanation:

let y = h(x) and rearrange making x the subject, that is

y = \frac{3}{4} x + 12 ( multiply through by 4 to clear the fraction )

4y = 3x + 48 ( subtract 48 from both sides )

4y - 48 = 3x ( divide both sides by 3 )

\frac{4y-48}{3} = x

Change y back into terms of x, thus

h^{-1} (x) = \frac{4x-48}{3}

3 0
3 years ago
Give answer as a fraction
FromTheMoon [43]

Answer:

1/6 or 16%

Step-by-step explanation:

There is a total of 150 students 87 boys and 63 girls

We see their is 25 boys with red hair

So we divide that amount by the total 25/150

We get 16% or 1/6

MARK AS BRAINLIEST

7 0
3 years ago
Read 2 more answers
Heres the picture, thank you!
Arte-miy333 [17]
Leg * /2 = hypotenuse
Hypotenuse divided by /2 = leg

12 divided by /2

Rationalize denominator:
12 * /2 divided by by /2 * /2

Simplify denominator:
12 * /2 divided by 2

Simplify:
6 * /2 or 4.24

Both x and y because it’s a 45-45-90 triangle
7 0
3 years ago
Read 2 more answers
Topic: The Quadratic Formula
Finger [1]

Answer:

Step-by-step explanation:

The quadratic formula for a equation of form

ax²+bx + c = 0 is

x= \frac{-b +- \sqrt{b^2-4ac} }{2a}

For the first equation,

x²+3x-4=0,

we can match that up with the form

ax²+bx + c = 0

to get that

ax² =  x²

divide both sides by x²

a=1

3x = bx

divide both sides by x

3 = b

-4 = c

. We can match this up because no constant multiplied by x could equal x² and no constant multiplied by another constant could equal x, so corresponding terms must match up.

Plugging our values into the equation, we get

x= \frac{-3 +- \sqrt{3^2-4(1)(-4)} }{2(1)} \\= \frac{-3+-\sqrt{25} }{2} \\ = \frac{-3+-5}{2} \\= -8/2 or 2/2\\=  -4 or 1

as our possible solutions

Plugging our values back into the equation, x²+3x-4=0, we see that both f(-4) and f(1) are equal to 0. Therefore, this has 2 real solutions.

Next, we have

x²+3x+4=0

Matching coefficients up, we can see that a = 1, b=3, and c=4. The quadratic equation is thus

x= \frac{-3 +- \sqrt{3^2-4(1)(4)} }{2(1)}\\= \frac{-3 +- \sqrt{9-16} }{2}\\= \frac{-3 +- \sqrt{-7} }{2}\\

Because √-7 is not a real number, this has no real solutions. However,

(-3 + √-7)/2 and (-3 - √-7)/2 are both possible complex solutions, so this has two complex solutions

Finally, for

4x² + 1= 4x,

we can start by subtracting 4x from both sides to maintain the desired form, resulting in

4x²-4x+1=0

Then, a=4, b=-4, and c=1, making our equation

x=\frac{-(-4) +- \sqrt{(-4)^2-4(4)(1)} }{2(4)} \\= \frac{4+-\sqrt{16-16} }{8} \\= \frac{4+-0}{8} \\= 1/2

Plugging 1/2 into 4x²+1=4x, this works as the only solution. This equation has one real solution

7 0
3 years ago
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