Answer:
12
Explanation:
20 words do be annoying
Answer:
I'm sorry, I think you mistyped, but the answer for this is 53.130997227947970715758049612623
Have a nice day! :)
-Vana
Answer:
Equation: ($26÷4 hours) × 25 hours
Answer: $156.25
Step-by-step explanation:
First, you would have to find out how much she earns per hour, so $26÷4. Then you multiply that by 25.
(26÷4) x 25=$156.25.
(hope this helps :P)
Answer:
b=-2aH
Step-by-step explanation:
H=-b/2a
Apply cross multiplication
H×2a=-b
2aH=-b
In the question you are to find positive b not negative b so you have to take negative b to the left hand side of the equation to become positive b and take 2aH to the right hand side to become -2aH
therefore b=-2aH
Answer:
a) OA = 1 unit
b) OB = 3 units
c) AB = √10 units
Step-by-step explanation:
<u>Given function</u>:

<h3><u>Part (a)</u></h3>
Point A is the y-intercept of the exponential curve (so when x = 0).
To find the y-value of Point A, substitute x = 0 into the function:

Therefore, A (0, 1) so OA = 1 unit.
<h3><u>Part (b)</u></h3>
If BC = 8 units then the y-value of Point C is 8.
The find the x-value of Point C, set the function to 8 and solve for x:

Therefore, C (3, 8) so Point B is (3, 0). Therefore, OB = 3 units.
<h3><u>Part (c)</u></h3>
From parts (a) and (b):
To find the length of AB, use the distance between two points formula:


Therefore:




