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Lesechka [4]
3 years ago
10

20 Points!! Please help

Mathematics
1 answer:
Setler79 [48]3 years ago
8 0

Answer:

The graph of the triangle LMN and the image L'M'N' created by rotation of ΔLMN through 180° made  with MS Excel is attached

The transformation involved in the 180° rotation of ΔLMN to create ΔL'M'N' includes;

The changing of the signs of the <em>x</em> and y-values of the coordinates of the vertices ΔLMN to get the corresponding <em>x</em> and y-values of the coordinates of the vertices of ΔL'M'N' as follows;

Before, rotation

The coordinates of the vertices of ΔLMN are; L(3, 3), M(9, 9), and N(9, 3)

After 180° rotation

The coordinates of the vertices of the image of ΔLMN, which is ΔL'M'N' are; L'(-3, -3), M'(-9, -9), and N'(-9, -3)

Therefore, the image of ΔLMN, ΔL'M'N' is located in the third quadrant, while the preimage ΔLMN is in the first quadrant

Part B

The lines drawn through L and L' and through M and M' are colinear lines

Part C

The lines dawn through points N and N' will not pass through the same line as the lines through L and L' and through M and M', because the three points are not colinear

Step-by-step explanation:

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Given:  In parallelogram DEFG,

DH = x + 1

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