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katovenus [111]
3 years ago
11

How is a decimal changed into a percent?

Mathematics
1 answer:
qwelly [4]3 years ago
8 0

Answer:

Move the decimal two places to the right and add a percent sign.

Step-by-step explanation:

.15= 15%

1.25= 125%

.06= 6.0, or 6%

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Ok so i hope this app works
castortr0y [4]

36 times 24 equals 864.


6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B7%7D%7B8%7D%20%2B%201%20%5Cfrac%7B1%7D%7B2%7D%20" id="TexFormula1" title=" \frac{
mart [117]

To add fractions together, you must convert the smaller fraction (\frac{1}{2}) to a denominator that matches the other fractions denominator.

In this case, 1/2 would become 4/8

We can add 4/8 to 7/8 to get 11/8

Then we can add the 1 to it, which acts as 8.

Which gives us 19/8

Or 2 3/8


5 0
3 years ago
Hey! please help posted picture of question
lara31 [8.8K]
The answer is D) 2

Since it is given that there have been 9 slices eaten, we can assume that whatever amount of slices were cut in total will have 9 reduced from the amount. With the fraction 2/11, we know 11-9=2, which fits perfectly into this description so 2 slices have not been eaten.
3 0
3 years ago
Read 2 more answers
Use the Factor Theorem and synthetic division to show x + 5 is a factor of f(x) = 2x3 + 7x2 − 14x + 5
olga2289 [7]

Answer:

Factor theorem: f(-5) = 0.

Synthetic division: f(x) = (x + 5)\, (2\, x^2 -3\, x + 1).

Step-by-step explanation:

<h3>Factor Theorem</h3>

By the factor theorem, a monomial of the form (x - a) (where a is a constant) is a factor of polynomial f(x) if and only if f(a) = 0.

In this question, the monomial is (x + 5), which is equivalently (x - (-5)). a = -5.

\begin{aligned}& f(-5) \\ &= 2 \times (-5)^{3} + 7 \times (-5)^{2}- 14\times (-5) + 5\\ &= -250 + 175 + 70 + 5 \\ &= 0\end{aligned}.

Hence, by the factor theorem,  (x + 5), which is equivalent to (x - (-5)), is a factor of f(x).

<h3>Synthetic Division</h3>

\begin{aligned}& f(x) \\ &= 2\, x^{3} + 7\, x^{2} - 14\, x + 5 \\ &= \underbrace{(x + 5) \, (2\, x^2)}_{2\, x^{3} + 10\, x^{2}} - 3\, x^{2} - 14\, x + 5 \\ &= \underbrace{(x + 5) \, (2\, x^2)}_{2\, x^{3} + 10\, x^{2}} + \underbrace{(x + 5)\, (-3\, x)}_{-3\, x^{2} - 15\, x} + (x + 5) \\ &= (x + 5)\, (2\, x^{2} - 3\, x + 1)\end{aligned}.

The remainder is 0 when dividing f(x) by (x + 5). Hence, (x + 5)\! is a factor of f(x)\!.

6 0
4 years ago
What values of a and b make the equation true?
mestny [16]

Answer:

3

Step-by-step explanation:

\sqrt{648} =\sqrt{2 * 2 * 2 * 3 * 3 * 3 * 3} \\\\=\sqrt{2^{3}*3^{4}}

a = 3 & b =4

6 0
3 years ago
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