All categories

2 years ago

Find the value of y 74 77 89 96

Mathematics

1 answer:

Morgarella [4.7K]2 years ago

4 0

The external angle (53°) is half the difference of the intercepted arcs (y°, 180°), so we have
53 = (180 - y)/2
106 = 180 - y
y = 180 - 106
y = 74

The appropriate choice for the value of y is ...
74

You might be interested in

300 is 100% of what number?

laiz [17]

300/x=100/100
(300/x)*x=(100/100)*x - we multiply both sides of the equation by x
300=1*x - we divide both sides of the equation by (1) to get x
300/1=x
300=x
x=300

now we have:
100% of 300=300

The answer is 300

8 0

2 years ago

Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains liters of a dye solution with a

Alja [10]

Answer:

t = 460.52 min

Step-by-step explanation:

Here is the complete question

Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains 200 liters of a dye solution with a concentration of 1 g/liter. To prepare for the next experiment, the tank is to be rinsed with fresh water flowing in at a rate of 2 liters/min, the well-stirred solution flowing out at the same rate.Find the time that will elapse before the concentration of dye in the tank reaches 1% of its original value.

Solution

Let Q(t) represent the amount of dye at any time t. Q' represent the net rate of change of amount of dye in the tank. Q' = inflow - outflow.

inflow = 0 (since the incoming water contains no dye)

outflow = concentration × rate of water inflow

Concentration = Quantity/volume = Q/200

outflow = concentration × rate of water inflow = Q/200 g/liter × 2 liters/min = Q/100 g/min.

So, Q' = inflow - outflow = 0 - Q/100

Q' = -Q/100 This is our differential equation. We solve it as follows

Q'/Q = -1/100

∫Q'/Q = ∫-1/100

㏑Q = -t/100 + c

$Q(t) = e^{(-t/100 + c)} = e^{(-t/100)}e^{c} = Ae^{(-t/100)}\\Q(t) = Ae^{(-t/100)}$

when t = 0, Q = 200 L × 1 g/L = 200 g

$Q(0) = 200 = Ae^{(-0/100)} = Ae^{(0)} = A\\A = 200.\\So, Q(t) = 200e^{(-t/100)}$

We are to find t when Q = 1% of its original value. 1% of 200 g = 0.01 × 200 = 2

$2 = 200e^{(-t/100)}\\\frac{2}{200} = e^{(-t/100)}$

㏑0.01 = -t/100

t = -100㏑0.01

t = 460.52 min

6 0

2 years ago

In a local basketball league championship total 198 games were played, where each team played exactly three games with all the o

kifflom [539]

Answer:

Step-by-step explanation:

When n teams play each other once, the total number of games is n(n-1)/2. Since each team played every other one 3 times, the relationship between number of teams (n) and number of games is ...

3(n(n-1)/2) = 198

n(n-1) = 132 = 12·11 . . . . . . multiply by 2/3 and factor

n = 12 . . . . . . n = -11 is also an extraneous solution to this quadratic equation

12 teams participated in this championship.

6 0

2 years ago

Please answer, Thank you. Image below.

Bezzdna [24]

Answer:

88°

Step-by-step explanation:

The triangle is an isosceles triangle, so two of the angles are both 46°. We also know that the sum of all the angles in any triangle is 180°, so we can set up the following equation:

46° + 46° + e = 180°

Solving this gets e = 88°.

8 0

1 year ago

HELP ASAPP I WILL GIVE BRAINLIEST

JulijaS [17]

6.667 yards I think I got it of safari

8 0

1 year ago

Read 2 more answers