Answer: B. 2 = 3x + 10x2
Step-by-step explanation:
This is the concept of quadratic equations; We required to find the type of equation that can be solved using the model that has been used to solve the equation such that the answer is:
[-3+-sqrt(3^2+4(10)(2))]/(2(10))
The formual that was applied here was a quadratic formula given by:
x=[-b+\-sqrt(b^2-4ac)]/2a
whereby from the our substituted values above,
a=10,b=3 and c=-2
such that the quadratic equation will be:
10x^2+3x-2
Answer: 96
seth got 18 more than frank
in terms of ratio he got 3 more than frank
this means that 3 is equal to 18
so we find the whole ratio to fing the total
Answer:
The probability that no more than 70% would prefer to start their own business is 0.1423.
Step-by-step explanation:
We are given that a Gallup survey indicated that 72% of 18- to 29-year-olds, if given choice, would prefer to start their own business rather than work for someone else.
Let
= <u><em>sample proportion of people who prefer to start their own business</em></u>
The z-score probability distribution for the sample proportion is given by;
Z =
~ N(0,1)
where, p = population proportion who would prefer to start their own business = 72%
n = sample of 18-29 year-olds = 600
Now, the probability that no more than 70% would prefer to start their own business is given by = P(
70%)
P(
70%) = P(
) = P(Z
-1.07) = 1 - P(Z < 1.07)
= 1 - 0.8577 = <u>0.1423</u>
The above probability is calculated by looking at the value of x = 1.07 in the z table which has an area of 0.8577.
Answer:
x = 1/5, y = 6
Step-by-step explanation:
5x + y = 7
y = 7 - 5x
Set equations equal to each other to eliminate y
7 - 5x = 20x + 2
7 = 25x + 2
5 = 25x
x = 1/5
y = 7 - 5(1/5)
y = 7 - 1
y = 6
121 is big enough to assume normality and not worry about the t distribution. By the 68-95-99.7 rule a 95% confidence interval includes plus or minus two standard deviations. So 95% of the cars will be in the mph range

The question is a bit vague, but it seems we're being asked for the 95% confidence interval on the average of 121 cars. The 121 is a hint of course.
The standard deviation of the average is in general the standard deviation of the individual samples divided by the square root of n:

So repeating our experiment of taking the average 121 cars over and over, we expect 95% of the averages to be in the mph range

That's probably the answer they're looking for.