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4 years ago

How many solutions does this have? 2x = 2x - 9 A. No B. One C. Two D. Infinity

Mathematics

2 answers:

Andru [333]4 years ago

8 0

Answer:

A. No solutions

Step-by-step explanation:

2x-2x=-9

0= -9

Since 0 does not equal -9, there are no solutions.

Andre45 [30]4 years ago

8 0

A:there is no solution

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${a}^{3} + {b}^{3} = (a + b)( {a}^{2 } - ab + {b}^{2} )$

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To find the expression that is equivalent to
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we must first expand
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Then we rearrange to find the required expression.

So let's get started.

${(a + b)}^{3} = (a + b) {(a + b)}^{2}$

We expand the parenthesis on the right hand side to get,

${(a + b)}^{3} = (a + b) ( {a}^{2} + 2ab + {b}^{2} )$

We expand again to obtain,

${(a + b)}^{3} = {a}^{3} + 3 {a}^{2}b + 3a {b}^{2} + {b}^{3}$

Let us group the cubed terms on the right hand side to get,

${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3 {a}^{2}b + 3a {b}^{2}$

${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3ab (a+ b)$

We make the cubed terms the subject,

${(a + b)}^{3} - 3ab (a+ b) = {a}^{3} + {b}^{3}$

We factor to get,

$(a + b)({(a + b)}^{2} - 3ab ) = {a}^{3} + {b}^{3}$

We expand the bracket on the left hand side to get,

$(a + b)( {a}^{2} + 2ab + {b}^{2} - 3ab ) = {a}^{3} + {b}^{3}$

We finally simplify to get,

$(a + b)( {a}^{2} - ab + {b}^{2} ) = {a}^{3} + {b}^{3}$

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